Is this a homework question? What do you mean mathematically, the question does not make sense mathmatically because one number is 187 million and the other is 1.87 billon, so they are not the same for any digits. If you take the last 1 off the second number, then the question makes sense from a mathematical standpoint, in which case you could use division dropping the remainder by each order of ten starting at the highest until the result is different.
Zaphod.
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cerdmannAuthor Commented:
I am using the number to represent (via base 8) the location of a node in a tree.
For example 187787852 = 1.63.7.42
(use the 8's as the decimal and clng(&o) the intermediary numbers to get the above.
Also,
1877814481 = 1.63.100.1
So these 2 numbers both fall under the node 1.63 (18778)
Instead of converting them to strings I would like to do the following functions (Example uses 1877814481):
Get parent 144 (100)
Get root 1 (1)
Get common parent (Example given in my first question)
I guess mathematically was incorrect. I should have said programmatically not using strings.
I am storing all base 8 numbers as variants cast from a SQL BigInt via cdec().
Could you somehow left shift the bits so that they line up and then do a bitwise comparison? I have no idea how to do this, but my research has given me this idea.
Some like this?
Function LShift(iVariable As Integer, _
iNumbits As Integer) As Integer
LShift = iVariable * (2 ^ iNumbits)
End Function
Function RShift(iVariable As Integer, _
iNumbits As Integer) As Integer
RShift = iVariable \ (2 ^ iNumbits)
End Function
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I already saw that article when I was researching this question however, I have never worked at the bit level and could use some help implementing it in my code.
Here is what I have thus far, just for switching between base 10 and base 8 (I know, I am using strings, but these functions will be rarily used)
Option Explicit
Private Sub Form_Load()
Debug.Print b8ConverttoBase10("1877814481")
Debug.Print b8ConverttoBase8("1.63.100.1")
End Sub
' =================================================================
' b8ConverttoString
' =================================================================
Public Function b8ConverttoBase10( _
ByVal Base8Number As Variant) As String
On Error GoTo ErrorHandler
Dim Base8String As String
Dim Base8Level() As String
Dim Base10Level() As String
Dim Levels As Long
Dim ArrayCounter As Long
Dim vntDecValue As Variant
Base8String = CStr(Base8Number)
Base8Level = Split(Base8String, "8")
Levels = UBound(Base8Level)
ReDim Base10Level(Levels)
For ArrayCounter = 0 To Levels
If Base8Level(ArrayCounter) <> "" Then
Base10Level(ArrayCounter) = CStr(CDec("&o" & Base8Level(ArrayCounter)))
End If
Next
Hi, why not convert it to a string, then do the comparison? Would this be much simpler and more readable than using bit manipulation? If I were you I would split the string into an array:
Dim arr() as string
Dim lngIndex as long
arr = split("1877814481","8")
for lngIndex = lbound(arr) to ubound(arr)
msgbox "Node" & arr(lngIndex)
next
To compare two to see if they have the same parents, just figure out which one is smaller, then iterate through both arrays until one of the elements is different.
BTW, I doubt you are going to find a way to get parent, or get root, purely mathematically. Your number is not a number, it is a sequence of numbers, and as such you should probably treat it as such in code.
If you do it that way and you have the parent to the right of the child, then you should be able to do everything mathematically, just be careful, the limit in VB for a long is 2 billion, 2,000,000,000, so you can only have 3 levels in your tree.
Zaphod.
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cerdmannAuthor Commented:
To find each level now becomes a simple modulus operation.
12080001 =
1

8

12
12080001 mod 10000 = 1
((12080001 mod 1000000)  (12080001 mod 10000))/10000 = 8
((12080001 mod 100000000)  (12080001 mod 1000000))/1000000 = 12
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cerdmannAuthor Commented:
We use SQL Server 2000 BigInt with a VB variant cast with the cdec() command
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cerdmannAuthor Commented:
Zaphod helped the most towards determining the right path, so I am awarding the points to him. Thanks for everyone's help.
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Zaphod.