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validate a number?

Hello all

I need a function that can tell if a number is, in fact, a number.
isdigit() does it for one char, but what about, ie, 25?

The function needs to be vanilla standard STL C++.

Thanks


Edmund
0
vlg
Asked:
vlg
  • 3
1 Solution
 
AxterCommented:
Do isdigit(char[0]).

Example:
const char* SomeNum = "25";

if (isdigit(SomeNum[0])) printf("It's a number");
0
 
AxterCommented:
If you want to check the full string for digits, you can use the following function.

bool IsStringDigit(const char* Src)
{
     int len = strlen(Src);
     if (!len) return false;
     for(int x = 0;x < len;++x)
     {
          if (!isdigit(Src[x])) return false;
     }
     return true;
}
0
 
jkrCommented:
You could also use wht the CRT offers - the 'strtoXX()' functions have a built-in check for number formats, so if you are dealing with ints, e.g.

#include <stdlib.h>

int n;
char* psz = "253";
char* stop;

n = (int) strtol ( psz, &stop, 10);

if ( *stop) {

 // if *stop is non-null, an invalid char was encountered
}


0
 
vlgAuthor Commented:
thanks everyone for their answers!
0
 
AxterCommented:
FYI:
You still have to check for he string length using the strtol method.

For example, with out checking for strlen, the following code would incorrectly interpret psz_bad2 as a number.

int n;
char* psz = "123";
char* psz_bad = "253x";
char* psz_bad2 = "";
char* stop;

n = (int) strtol ( psz, &stop, 10);
if (!stop[0]) printf("Is a number\n");
else printf("Not a number (%s)\n", stop);

n = (int) strtol ( psz_bad, &stop, 10);
if (!stop[0]) printf("Is a number\n");
else printf("Not a number (%s)\n", stop);

n = (int) strtol ( psz_bad2, &stop, 10);
if (!stop[0]) printf("Is a number\n");
else printf("Not a number (%s)\n", stop);

0
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