Servlet Headers

We are trying to create a servlet that we can call and stream the information in and out of the servlet so the user does not know where the information is that they are interacting with.  

If a user clients on a link we call our servlet passing in the link and the servlet gets the page information and streams it back to our client.  The problem is that if the page is interactive we need to know how to retrieve the posted information in our servlet and send it to the server that the page resides on then when that page returns the results we send them back to the client.  

So we need to know how to read the posted information either in the query string or the form and then re-package it and send it to the correct page.

Ok.

Well if the form is GET (means all the parameters)
are in the QueryString..

Then use request.getQueryString() to retrieve all the parameters and values and pass them to the other page.

If the form is a POST. its a little more work.
String queryStr = "?";
java.util.Enumeration formFieldNames = request.getParameterNames();
while (formFieldNames.hasMoreElements()) {
  String currentFormFieldName = (String) formFieldNames.nextElement();
  queryStr += java.net.URLEncoder.encode(currentFormFieldName) + "=" + java.net.URLEncoder.encode(request.getParameter(currentFormFieldName)) + "&";
}

Now you can use queryStr to pass the vars to the other page.

if you can just do a response.sendRedirect() then you are done.. but if you need to actually post to the other page and have the servlet continue handling everything then it is a bit more complicated.

This article will help in how to post to other CGIs using Java:
http://www.javaworld.com/javatips/jw-javatip34.html

HTH,
CJ

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IMHO, I have provided enough info for CodeHead to start coding a solution, so if the pts are awarded they should go to me.

CJ

Thank you for returning and grading.  Thanx for the "A".

CJ