?
Solved

printing a char in graphics mode

Posted on 2002-05-04
3
Medium Priority
?
379 Views
Last Modified: 2010-04-02
How can I print a character in graphics mode with the
outtextxy function? I'm doing the following:

#include <graphics.h>
#include <conio.h>
#include <iostream.h>
#include <stdlib.h>
#include <ctype.h>


void main()
{

   int gdriver = DETECT, gmode;
   int Errcode   ;
   char key;

 initgraph(&gdriver,&gmode,"D:\\BORLAND\\BORLANDC\\BGI\\") ;
 Errcode = graphresult();
 if (Errcode != grOk)
    {
      cout<<"Graphics Error:"<< grapherrormsg(Errcode);
      exit(1);
    }
     setcolor(15);
     key=getch();        
     outtextxy(10,30,key);
}

How can I print key with this function?


Thanks in advance

   AFM





 
0
Comment
Question by:AngelFireMateo
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
3 Comments
 
LVL 1

Accepted Solution

by:
jdrescher earned 150 total points
ID: 6991306
You are still using borland BGI graphics? I have not done this in the last 6+ years..

Here is my guess. I assume outtextxy takes a string and you are giving it a char. I'm sorry if this is totally off base but I don't have any access to borland bgi anymore.

void main()
{

  int gdriver = DETECT, gmode;
  int Errcode   ;
  char key[2];

initgraph(&gdriver,&gmode,"D:\\BORLAND\\BORLANDC\\BGI\\") ;
Errcode = graphresult();
if (Errcode != grOk)
   {
     cout<<"Graphics Error:"<< grapherrormsg(Errcode);
     exit(1);
   }
    setcolor(15);
    key[0]=(char)getch();        
    key[1]='\0';
    outtextxy(10,30,key);
}

John
0
 

Expert Comment

by:baclay
ID: 6992166
John's code does solve your problem and here is an alternative that I came up with.

Barry


#include <graphics.h>
#include <conio.h>
#include <iostream.h>
#include <stdlib.h>
#include <ctype.h>


struct key_word
{
   unsigned int key_code;
};

struct key_bytes
{
   unsigned char ascii;
   unsigned char scan_code;
};

union key_fields
{
   struct key_word kw;
   struct key_bytes kb;
};


union key_fields key;

void main()
{

  int gdriver = DETECT, gmode;
  int Errcode;
  int c;
  char msgbuf[80];

  initgraph(&gdriver, &gmode, "D:\\BORLAND\\BORLANDC\\BGI\\") ;
  Errcode = graphresult();

  if (Errcode != grOk)
    {
      cout<<"Graphics Error:"<< grapherrormsg(Errcode);
      exit(1);
    }

  setcolor(15);

  key.kw.key_code = getch();


  memset(msgbuf , '\0', 80);
  msgbuf[0] = key.kb.ascii;

  outtextxy(10, 30, msgbuf);
} // end main()
0
 
LVL 1

Author Comment

by:AngelFireMateo
ID: 7150100
it works well thanks
0

Featured Post

What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Templates For Beginners Or How To Encourage The Compiler To Work For You Introduction This tutorial is targeted at the reader who is, perhaps, familiar with the basics of C++ but would prefer a little slower introduction to the more ad…
Container Orchestration platforms empower organizations to scale their apps at an exceptional rate. This is the reason numerous innovation-driven companies are moving apps to an appropriated datacenter wide platform that empowers them to scale at a …
The viewer will learn how to user default arguments when defining functions. This method of defining functions will be contrasted with the non-default-argument of defining functions.
The viewer will learn additional member functions of the vector class. Specifically, the capacity and swap member functions will be introduced.
Suggested Courses
Course of the Month11 days, 12 hours left to enroll

752 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question