Throwing exceptions from static initialization code

If you want to throw an Exception, you need to write:

public static void X() throws Exception
{
  // Throws Exception
}

When you write "throws Exception", you are forced to make a try catch around your method calling X, or make that method throws Exception.

If you want to avoid writing throws Exception, throw a RuntimeException instead. This way, you are not forced to make a try catch.

public static void X()
{
  // Throws RuntimeException
}

> There is a way to declare that the static initialization code throws a Exception ?

what do you need this for ?

I need throwing a Exception, because the code effectively throws a Exception. Of course I can use a boolean variable and ask for that variable in every method of my class.
I ask the question because I didn't know if it was possible to throw a Exception from a static initialization block. If it's impossible, OK, let's find another way !!!

Thanks everybody.

you can always and everywhere throw RuntimeException (like NullPointerException)

And in this case it makes sense to throw
    ExceptionInInitializerError
like this...

-------StaticCode.java-------cut here-------8<-------
public class StaticCode
{
    public static final long[] a = new long[1];
   
    static
    {
        a[0]=Math.round( Math.random() );
       
        if (a[0]==0)
        {
            throw new ExceptionInInitializerError( "...is being thrown when a[0] is initialized to 0" );
        }
    }
   
} /* StaticCode */
-------StaticCode.java-------cut here-------8<-------


-------statictest.java-------cut here-------8<-------
public class statictest
{
    public static void main( String[] args )
    {
        System.out.println( "Start." );
        long a = StaticCode.a[0];
        System.out.println( "a="+a );
        System.out.println( "Done." );
    }
   
} /* statictest */
-------statictest.java-------cut here-------8<-------

Greetings,
    </ntr> :)