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xsl:Include

I am trying to use xsl:include am am having no luck. Below are the two XSL Files (MAIN.XSL and HEADER.XSL) that i need assistance with.

MAIN.XSL
=================

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:template match="page">
  <xsl:for-each select="element">
    <xsl:if test="type/text()='header'">
     <xsl:call-template name="header" />
    </xsl:if>
  </xsl:for-each>
 </xsl:template>
 <xsl:include href="header.xsl" />
</xsl:stylesheet>

HEADER.XSL
==================

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:template name="header">
  <table width="100%" border="0">            
   <tr><td><img src="images/header_left.gif" /></td></tr>
  </table>
 </xsl:template>
</xsl:stylesheet>

=============================
The error message being returned is:

msxml4.dll (0x80004005)
The system cannot locate the object specified. Error occurred during compilation of included or imported stylesheet 'header.xsl'.

==============================

Please note that if i replace the line in MAIN.XSL:

<xsl:include href="header.xsl" />

With:

 <xsl:template name="header">
  <table width="100%" border="0">            
   <tr><td><img src="images/header_left.gif" /></td></tr>
  </table>
</xsl:template>

The transformation works perfectly.

Also note that MAIN.XSL & HEADER.XSL reside in the same directory.

Thanks


0
greenrc
Asked:
greenrc
  • 5
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1 Solution
 
b1xml2Commented:
how do you use the XSLT documents
==================================
Under VB, everything works fine with straight transforms as well as using the XSLTemplate

Under ASP, everything works fine with straight transforms as well as using the XSLTemplate

Under the client, everything works fine with straight transforms as well as using the XSLTemplate.

Tell me where and how are you getting the said error?
0
 
greenrcAuthor Commented:
I am transforming the files with the following ASP code:
=============================
Set oXmlDoc = Server.CreateObject("Msxml2.DOMDocument.4.0")
Set oXslDoc = Server.CreateObject("Msxml2.DOMDocument.4.0")
Set pagexml = FSO.OpenTextFile(Server.MapPath("xml/page.xml"), ForReading, False, TristateTrue)
strXml = pagexml.ReadAll()
pagexml.close
oXmlDoc.loadXML strXml
oXmlDoc.setProperty "SelectionLanguage", "XPath"    

Set strXsl = FSO.OpenTextFile(Server.MapPath("xsl/page.xsl"), ForReading, False, TristateTrue)
oXslDoc.loadXML strXsl.ReadAll()
strXsl.close

PageHTML = oXmlDoc.transformNode(oXslDoc)

XML is as follows:
======================
<xml>
 <page>
  <element>
   <type>header</type>
  </element>
 </page>
</xml>
0
 
greenrcAuthor Commented:
Error is a server side ASP Transformation error.
0
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greenrcAuthor Commented:
Sorry XSL path S/B

Server.MapPath("xsl/main.xsl"), ....
0
 
b1xml2Commented:
The ASP Code you used is incorrect.
===========================================
<%
Dim oXmlDoc, oXslDoc
Set oXmlDoc = Server.CreateObject("Msxml2.DOMDocument.4.0")
Set oXslDoc = Server.CreateObject("Msxml2.DOMDocument.4.0")
oXmlDoc.async = False
oXslDoc.async = False
oXmlDoc.load Server.MapPath("xml/page.xml")
oXslDoc.load Server.MapPath("xsl.main.xsl")
oXmlDoc.transformNodeToObject oXslDoc, Response
Set oXmlDoc = Nothing
Set oXslDoc = Nothing
%>

Notes
=====
1. The problem with the linking is that you are using the FileSystemObject to load the file and pass it into a variable and then load it via the loadXML method. Now whenever documents are loaded via the loadXML method, the starting point of the url is taken from the existing asp  page and thus, it is looking for header.xsl in the same directory as the asp page.

2. By using the load method along with the Server.MapPath method, you will be using the url of the XSLT document as the starting point to find the included XSLT document.

Regards,

Brandon Driesen
0
 
b1xml2Commented:
typo with path
====
<%
Dim oXmlDoc, oXslDoc
Set oXmlDoc = Server.CreateObject("Msxml2.DOMDocument.4.0")
Set oXslDoc = Server.CreateObject("Msxml2.DOMDocument.4.0")
oXmlDoc.async = False
oXslDoc.async = False
oXmlDoc.load Server.MapPath("xml/page.xml")
oXslDoc.load Server.MapPath("xsl/main.xsl")
oXmlDoc.transformNodeToObject oXslDoc, Response
Set oXmlDoc = Nothing
Set oXslDoc = Nothing
%>
0
 
b1xml2Commented:
green, it's been a while. Feedback please.
0
 
b1xml2Commented:
green, second call =)
0
 
greenrcAuthor Commented:
oXmlDoc.load works ... excellent!

Thanks again Brandon.


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