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Text compare

Posted on 2002-05-13
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Last Modified: 2010-05-02
i having problem text compare where user enter value in text box. i need to make sure is alphanumeric format and no (!, @, #, $, %, ^, etc) format.

how to i write a code to check on this. if i found  !,@ #, etc in the text box then will prompt a mesasge "Wrong format".


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Question by:cyseng10
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9 Comments
 
LVL 43

Expert Comment

by:TimCottee
ID: 7005542
Private Sub Text1_KeyPress(KeyAscii As Integer)
    Select Case Chr(KeyAscii)
    Case "0" To "9" 'Numbers
    Case "a" To "z" 'Lower case
    Case "A" To "Z" 'Upper case
    Case " ", Chr(8) 'Space or delete keys
    Case Else 'Not a valid key so set the keyascii = 0 to ignore the keypress
        KeyAscii = 0
    End Select
End Sub
0
 
LVL 43

Expert Comment

by:TimCottee
ID: 7005544
Actually this does the validation as the key is pressed so that you can be sure that it will always include only alphanumeric characters and spaces.
0
 
LVL 45

Expert Comment

by:aikimark
ID: 7005835
TimCottee,

What happens if the user pastes characters into the textbox?
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LVL 43

Expert Comment

by:TimCottee
ID: 7005849
Good point though as Ctrl+V is disabled it would have to be done on the context menu and this could be disabled using the mousedown event.


Private Sub Text1_MouseDown(Button As Integer, Shift As Integer, X As Single, Y As Single)
    If Button = 2 Then
        MsgBox "Ha Ha"
    End If
End Sub
0
 
LVL 18

Expert Comment

by:deighton
ID: 7006202
Option Explicit

Private Declare Function IsCharAlphaNumeric Lib "user32" Alias "IsCharAlphaNumericA" (ByVal cChar As Byte) As Long

Private Sub Text1_Change()
Dim c As Long
Dim sTest

Dim k

k = Text1.SelStart



For c = 1 To Len(Text1.Text)
    If IsCharAlphaNumeric(Asc(Mid(Text1, c, 1))) = 1 Then
        sTest = sTest & Mid(Text1, c, 1)
    End If
Next

If Len(sTest) <> Len(Text1.Text) Then
    Text1 = sTest
    Text1.SelStart = k
End If



End Sub

Private Sub Text1_KeyPress(KeyAscii As Integer)
If Not (IsCharAlphaNumeric(KeyAscii) <> 0 Or KeyAscii = vbKeyBack) Then
 KeyAscii = 0
End If
End Sub
0
 
LVL 18

Expert Comment

by:deighton
ID: 7006206
Option Explicit

Private Declare Function IsCharAlphaNumeric _
Lib "user32" Alias "IsCharAlphaNumericA" (ByVal cChar As Byte) As Long

Private Sub Text1_Change()
Dim c As Long
Dim sTest

Dim k

k = Text1.SelStart



For c = 1 To Len(Text1.Text)
    If IsCharAlphaNumeric(Asc(Mid(Text1, c, 1))) = 1 Then
        sTest = sTest & Mid(Text1, c, 1)
    End If
Next

If Len(sTest) <> Len(Text1.Text) Then
    Text1 = sTest
    Text1.SelStart = k
End If



End Sub

Private Sub Text1_KeyPress(KeyAscii As Integer)
If Not (IsCharAlphaNumeric(KeyAscii) <> 0 Or KeyAscii = vbKeyBack) Then
 KeyAscii = 0
End If
End Sub

0
 
LVL 45

Expert Comment

by:aikimark
ID: 7006323
Of course, there is a VBA alternative to IsCharAlphaNumeric API.  You only need extra validation if you allow the user to paste into the textbox.

strTemp = Text1.Text
for i=1 to len(strTemp)
  if mid$(strTemp,i,1) like "[A-Z,a-z,0-9]"
next

Also, if you don't want to allow spaces into the textbox, you will need to modify TimCottee's fourth Case clause.
0
 
LVL 1

Expert Comment

by:Moondancer
ID: 7017651
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