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DatDiff("t";[Opening];30.06.##)

Posted on 2002-05-13
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Last Modified: 2012-05-04
I do need to make a billing in Mid-June for the 1H-Year for the customers. The period to calculate is from the opening or 01.01. of the relationsship to the End of June (30.06.). This has to be done every year, so I cannot use 30.06.2002 to calculate the DatDiff. But if I use only 30.06., the system reports an error. I actually use

If([J]=[Jr] and [Mt] between 1 and 6;DatDiff("t";[Opening];"30.06.##");"180")

Any idea how to solve the problem?
Thanks
ColumA
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Question by:ColumA
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3 Comments
 
LVL 143

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 7005567
Try this:

If([J]=[Jr] and [Mt] between 1 and 6;DatDiff("t";[Opening];"30.06." & Year(now)  );"180")

CHeers
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LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 150 total points
ID: 7005570
or, assuming that [J] and [Jr] contain the year values:

If([J]=[Jr] and [Mt] between 1 and 6;DatDiff("t";[Opening];"30.06." & [J] );"180")

CHeers

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Author Comment

by:ColumA
ID: 7005619
Thank you for the prompt answer.
Rgds
ColumA
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