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label control and hwnd

Posted on 2002-05-15
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Last Modified: 2012-06-27
is there a way to get the hwnd of a label control


i want to use the following api

GetClientRect  label.hwnd, lpRect
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Question by:RYMENHOUT
9 Comments
 
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Expert Comment

by:mirtol
ID: 7010698
A label has no window. It is printed on the parent's dc.

If u need to do something with it, use a text control.
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LVL 45

Expert Comment

by:aikimark
ID: 7010877
Please delete your duplicate question.
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Expert Comment

by:corvanderlinden
ID: 7010943
mirtol is right

Info
Label is a windowless control just like
Line
Shape
Image
and the controls in the MSWLess.ocx shipped with VB6
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Expert Comment

by:aikimark
ID: 7011006
Can you use the Form's hwnd and specify the size & location of the label directly from its properties?
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Author Comment

by:RYMENHOUT
ID: 7011178
IT IS ON A USERCONTROL
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aikimark earned 50 total points
ID: 7011202
use the user control's hWnd and offset the label's position by the position of the user control's position.
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Expert Comment

by:Richie_Simonetti
ID: 7011575
Try with:
Private Type RECT
        Left As Long
        Top As Long
        Right As Long
        Bottom As Long
End Type
Private Declare Function GetWindowRect Lib "user32" (ByVal hwnd As Long, lpRect As RECT) As Long

Private Sub Form_Load()
Dim r As RECT

With Label1
     r.Top = .Top
     r.Right = .Left + .Width
     r.Bottom = .Top + .Height
     r.Left = .Left
End With
GetWindowRect Me.hwnd, r
End Sub

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by:DanRollins
ID: 7765582
Hi RYMENHOUT,
It appears that you have forgotten this question. I will ask Community Support to close it unless you finalize it within 7 days. I will ask a Community Support Moderator to:

    Accept aikimark's comment(s) as an answer.

RYMENHOUT, if you think your question was not answered at all or if you need help, just post a new comment here; Community Support will help you.  DO NOT accept this comment as an answer.

EXPERTS: If you disagree with that recommendation, please post an explanatory comment.
==========
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Expert Comment

by:SpideyMod
ID: 7838363
per recommendation

SpideyMod
Community Support Moderator @Experts Exchange
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