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recognize upper & lower cases

Posted on 2002-05-18
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Last Modified: 2011-09-20
is there a way to count the number of upper and lower case entered in a string..having in mind that the user might enter other than letters..like spaces and other characters..
plus i have to add all the characters in that string..
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Question by:ms_lost
11 Comments
 
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Expert Comment

by:objects
ID: 7019076
The Character class has various methods for checking character types, including isLowerCase() and isUpperCase().
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Author Comment

by:ms_lost
ID: 7019172
yeah but how to check that.. since the user will enter a string mix of both
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Assisted Solution

by:objects
objects earned 45 total points
ID: 7019176
Just loop thru the string checking each character:

int lc = 0;
for (int i=0; i<s.length(); i++)
{
  if (Character.isLowerCase(s.charAt(i))) lc++;
}
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Accepted Solution

by:
Jim Cakalic earned 45 total points
ID: 7021786
That will work, although a more performant solution would get the char[] of the String instead of using charAt:

    char[] chars = str.toCharArray();
    for (int i = chars.length - 1; i >= 0; --i) {
        ++numChars;
        if (Character.isLowerCase(chars[i])) {
            ++numLower;
        } else if (Character.isUpperCase(chars[i])) {
            ++numUpper;
        }
    }

Jim
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Expert Comment

by:objects
ID: 7022713
Sorry, I was just focussing on the question and how to count lower case character, and was not convcerned with the performance. And as the string was being entered by the user, and as such would generally be short, then the performance difference would be minimal anyway.
If you really wanted a fast solution that would handle long strings then looping thru the string is not the answer anyway :)
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LVL 92

Expert Comment

by:objects
ID: 7022956
If performance is an issue then the following is a better solution:

char[] c = Arrays.sort((s+"azAZ").toCharArray());
int nlower = Arrays.binarySearch(c, 'z') -
   Arrays.binarySearch(c, 'a') - 1;
int nupper = Arrays.binarySearch(c, 'Z') -
   Arrays.binarySearch(c, 'A') - 1;
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LVL 19

Expert Comment

by:Jim Cakalic
ID: 7023978
Hmm. Didn't mean to sound as if I was criticizing -- just extending your remarks. (At least I didn't post as an answer, eh?)

Jim
:-)
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Expert Comment

by:objects
ID: 7025506
No offence taken :-)
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Expert Comment

by:girionis
ID: 8766847
No comment has been added lately, so it's time to clean up this TA.

I will leave a recommendation in the Cleanup topic area that this question is:

- split points between objects@idg and jim_cakalic@idg

Please leave any comments here within the
next seven days.

PLEASE DO NOT ACCEPT THIS COMMENT AS AN ANSWER !

girionis
Cleanup Volunteer
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Expert Comment

by:Jim Cakalic
ID: 8766874
Friday is _cleanup_ day! OK by me. :-)
Jim
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