syntel
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Launching a File
Hi all,
In function I need to run a file outside of my app, just as if the user had clicked on the filename. It could be a Word document, Zip file, *.Htm, *.exe, etc. I used to do this in batch files by using: Start("Path/Filname") or similar syntax in Win98.
In application the user will double-click on a filename to be found in some text displayed in link format in my app window.
The platform would be any Windows 98/Me/NT5. I'm using VB6.
Any ideas are appreciated.
Jim
In function I need to run a file outside of my app, just as if the user had clicked on the filename. It could be a Word document, Zip file, *.Htm, *.exe, etc. I used to do this in batch files by using: Start("Path/Filname") or similar syntax in Win98.
In application the user will double-click on a filename to be found in some text displayed in link format in my app window.
The platform would be any Windows 98/Me/NT5. I'm using VB6.
Any ideas are appreciated.
Jim
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Thanks for all responses. I will be working on this next week, but it looks good.
thanks for the grade
http://www.freevbcode.com/ShowCode.Asp?ID=525