andysalih
asked on
time problem
Doesn anybody know how to calculate a time difference,
when i write some code to get the result of say (9pm - 8am) it keeps adding 12 hours on.
but if i do it from 1am - 6am then it works the time out correct.
can somebody show me some code that gives me the hours difference from 8pm - 6am.
cheers
Andy
when i write some code to get the result of say (9pm - 8am) it keeps adding 12 hours on.
but if i do it from 1am - 6am then it works the time out correct.
can somebody show me some code that gives me the hours difference from 8pm - 6am.
cheers
Andy
hi andysalih,
Try this,
X = Abs(DateDiff("H", "21:00:00", "8:00:00"))
where the time is in 24hr format
hope this helps!
-priya
Try this,
X = Abs(DateDiff("H", "21:00:00", "8:00:00"))
where the time is in 24hr format
hope this helps!
-priya
Oops - now I get what you mean. Since the datediff function also gives you the same problem, how about reversing the time? As in...
Instead of:
MsgBox DateDiff("h", "8:00 PM", "6:00 AM")
You do something like:
MsgBox DateDiff("h", "6:00 PM", "8:00 AM")
Of course, you'll need some coding to determine is the switching is required by using the instr function to check for 'AM' or 'PM'
That's it!
glass cookie ; )
Instead of:
MsgBox DateDiff("h", "8:00 PM", "6:00 AM")
You do something like:
MsgBox DateDiff("h", "6:00 PM", "8:00 AM")
Of course, you'll need some coding to determine is the switching is required by using the instr function to check for 'AM' or 'PM'
That's it!
glass cookie ; )
therefore X would return "13"
Hello,
if the two 'times' are not within the same day you've got to use the date to tell the DateDiff function what to do
DateDiff("H", "01/01/2002 21:00:00", "01/02/2002 8:00:00")
if the two 'times' are not within the same day you've got to use the date to tell the DateDiff function what to do
DateDiff("H", "01/01/2002 21:00:00", "01/02/2002 8:00:00")
ASKER
i dont understand the calcs here
in my world 9pm - 8am in the morning is 11 hours, How can it be 13.
why is it returning the value 13
cheers
Andy
in my world 9pm - 8am in the morning is 11 hours, How can it be 13.
why is it returning the value 13
cheers
Andy
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ASKER
i dont understand the calcs here
in my world 9pm - 8am in the morning is 11 hours, How can it be 13.
why is it returning the value 13
cheers
Andy
in my world 9pm - 8am in the morning is 11 hours, How can it be 13.
why is it returning the value 13
cheers
Andy
ASKER
oops. REFRESHED by mistake sorry guys
'Formatted:
Private Sub Command1_click()
MsgBox DateDiff("H", Format("27/07/2002 21:00:00", "dd-mm-yyyy hh:mm:ss"), Format("28/07/2002 08:00:00",
"dd-mm-yyyy hh:mm:ss"))
'the above returns 11
MsgBox DateDiff("H", Format("27/07/2002 20:00:00", "dd-mm-yyyy hh:mm:ss"), Format("28/07/2002 06:00:00", "dd-mm-yyyy hh:mm:ss"))
'this returns 10
End Sub
-priya
ASKER
thats the one,
cheers
Andy
cheers
Andy
You could use the datediff function to do that. Here's the extract from my help file (use 'h'):
Returns a Variant (Long) specifying the number of time intervals between two specified dates.
Syntax
DateDiff(interval, date1, date2[, firstdayofweek[, firstweekofyear]])
The DateDiff function syntax has these named arguments:
Part Description
interval Required. String expression that is the interval of time you use to calculate the difference between date1 and date2.
date1, date2 Required; Variant (Date). Two dates you want to use in the calculation.
firstdayofweek Optional. A constant that specifies the first day of the week. If not specified, Sunday is assumed.
firstweekofyear Optional. A constant that specifies the first week of the year. If not specified, the first week is assumed to be the week in which January 1 occurs.
Settings
The interval argument has these settings:
Setting Description
yyyy Year
q Quarter
m Month
y Day of year
d Day
w Weekday
ww Week
h Hour
n Minute
s Second
That's it!
glass cookie : )