char char char char char char char char...

char *mychar;
char a = '1';
char b = '2';
char c = '3';
char d = '4';
I want to put a,b,c and d in the mychar. So, mychar should be equal "1234". I don't want it like
char *mychar="1234";
I want somehow put these 4 chars seperatly.
Thats not my homework :)
rv_manAsked:
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ChenChenCommented:
Try this:
#include <stdio.h>

     char *mychar;
     char a='a';
     char b='b';
     char c='c';
     char d='d';

     mychar=(char *)malloc((4+1)*sizeof(char));
     sprintf(mychar,"%c%c%c%c",a,b,c,d);
     printf("MyChar is %s\n",mychar);
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rv_manAuthor Commented:
Will I get booted for my stupid questions?
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Jan LouwerensSoftware EngineerCommented:
char a = '1';
char b = '2';
char c = '3';
char d = '4';
char* mychar = new char[5];
mychar[0] = a;
mychar[1] = b;
mychar[2] = c;
mychar[3] = d;
mychar[4] = '\0';
...
delete [] mychar;
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ozoCommented:
char mychar[] = {a,b,c,d};

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Jan LouwerensSenior DeveloperCommented:
That accepted answer actually has a bug in which the string is not properly ended with a NULL terminator
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DanRollinsCommented:
char szCombined[5];
char* p= szCombined;
*p++ = a;
*p++ = b;
*p++ = c;
*p++ = d;
*p= '\0;
printf("szCombined is %s\n", szCombined );
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