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DWORD

Posted on 2002-06-02
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Last Modified: 2008-03-06
Hi, I'm newbie in c++ and I can't solve this probllem:


I have:
char * mychar = "0xffff0000";
DWORD color;

I want to put mychar into color like I usually do:
color = 0xffff0000;



Tnx.
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Question by:Romonnn
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4 Comments
 
LVL 86

Expert Comment

by:jkr
ID: 7049687
use 'strtol()':

#include <stdlib.h>

cahr * pc;
char * mychar = "0xffff0000";
DWORD color;

color = strtol ( mychar, &pc, 16); // 16 indicates hex numeric base

if ( *pc) {
// error
}
0
 

Author Comment

by:Romonnn
ID: 7049766
jkr, this is the best answer on my question. But, the output of strtol still not the same. The output is 2147483647 but it should be 4294901760 (approximately 2 * 2147483647). As a newbie i tried 32 as 3 argument of strtol(output 0). I still don't know what to do :(



#include <stdlib.h>
#include <iostream.h>
#include <windows.h>


int main(){


char * pc;
char * mychar = "0xffff0000";
DWORD color;
DWORD color2 = 0xffff0000;

color = strtol ( mychar, &pc, 16); // 16 indicates hex numeric base

cout << color << endl;
cout << color2 << endl;


if ( *pc) {
// error
}
}
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LVL 86

Accepted Solution

by:
jkr earned 400 total points
ID: 7049773
My fault - use "strtoul()" instead...
0
 

Author Comment

by:Romonnn
ID: 7049810
Tnx. Everything works fine :)
0

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