Solved

The exception is not handled

Posted on 2002-06-04
6
171 Views
Last Modified: 2010-03-31
Why the following code get the error: "The exception java.lang.Exception is not handled."?

public void performTask(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response)         throws ServletException
{
     super.performTask(request, response);
    String cmdName = null;
    Command cmd = null;
    CommandMapObject mapObj = null;
     Result result = new Result();
     try{
          mapObj = this.getCmdMap().getCommandMapObject(this.getCmdName(request));
                  if (this.getCmdName(request).equalsIgnoreCase("login")){
                       this.login(request);
                       result.setTargetName("success");        
                  }else {
                       this.logout(request);
                          result.setTargetName("success");
                  }

                  forward(request, response, mapObj, result);
       
         } catch (SignOnException se) {
              result.setObject("errorMsg", se.getMessage());
              request = setRequestParameters(request, mapObj, result);
              result.setTargetName("fail");
              forward(request, response, mapObj, result);
         } catch (Exception e) {
                  throw new ServletException(e.getMessage());
         }
}
0
Comment
Question by:DevelHelper
  • 4
  • 2
6 Comments
 
LVL 4

Accepted Solution

by:
pellep earned 50 total points
ID: 7054203
does the performTask() function in the superclass throw 'Exception'. If so, you need to catch it when you call super.performTask(request, response);
0
 

Author Comment

by:DevelHelper
ID: 7054275
public void doPost(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException
    {
        performTask(request, response);
    }
0
 
LVL 4

Expert Comment

by:pellep
ID: 7054294
try

public void performTask(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse
response)         throws ServletException
{

   
   String cmdName = null;
   Command cmd = null;
   CommandMapObject mapObj = null;
    Result result = new Result();
    try{
         super.performTask(request, response);
         mapObj = this.getCmdMap().getCommandMapObject(this.getCmdName(request));
                 if (this.getCmdName(request).equalsIgnoreCase("login")){
                      this.login(request);
                      result.setTargetName("success");        
                 }else {
                      this.logout(request);
                         result.setTargetName("success");
                 }

                 forward(request, response, mapObj, result);
       
        } catch (SignOnException se) {
             result.setObject("errorMsg", se.getMessage());
             request = setRequestParameters(request, mapObj, result);
             result.setTargetName("fail");
             forward(request, response, mapObj, result);
        } catch (Exception e) {
                 throw new ServletException(e.getMessage());
        }
}
0
Free Tool: Subnet Calculator

The subnet calculator helps you design networks by taking an IP address and network mask and returning information such as network, broadcast address, and host range.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

 

Author Comment

by:DevelHelper
ID: 7054318
I tried your code, but got the same compile error.
0
 
LVL 4

Expert Comment

by:pellep
ID: 7055714
doesn't the compile error include any indication as to where the error occured (filename, line-number or the likes)?
0
 
LVL 4

Expert Comment

by:pellep
ID: 7055723
it could also be the call to forward(request, response, mapObj, result);
within the first catch section.
0

Featured Post

Free Tool: Path Explorer

An intuitive utility to help find the CSS path to UI elements on a webpage. These paths are used frequently in a variety of front-end development and QA automation tasks.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
javap not working 8 59
MySqlDump not dumping triggers 1 43
Notify sent to other threads in Java 9 33
What is the use of Forwarding Class in java 1 16
Java Flight Recorder and Java Mission Control together create a complete tool chain to continuously collect low level and detailed runtime information enabling after-the-fact incident analysis. Java Flight Recorder is a profiling and event collectio…
In this post we will learn how to connect and configure Android Device (Smartphone etc.) with Android Studio. After that we will run a simple Hello World Program.
Video by: Michael
Viewers learn about how to reduce the potential repetitiveness of coding in main by developing methods to perform specific tasks for their program. Additionally, objects are introduced for the purpose of learning how to call methods in Java. Define …
Viewers will learn one way to get user input in Java. Introduce the Scanner object: Declare the variable that stores the user input: An example prompting the user for input: Methods you need to invoke in order to properly get  user input:

828 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question