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Selecting a record by row number in MS SQL

How can I achieve the following in MS SQL ?
a) Selecting a record from the Nth position(row) of a table.
b) selecting a record which is between nth and mth position in a SQL server table.

Assuming table is ordered with a key, which can be varchar. We won;t be knowing the key value, but only the position.

In Oracle we can use rownum. what are options in MS SQL ?

Thanks in advance
Renjith
0
renjith
Asked:
renjith
1 Solution
 
Guy Hengel [angelIII / a3]Billing EngineerCommented:
either
* insert all the key values to a table with autonumber and key information, and then select with join.
* using a cursor (very slooooooooooooow)

CHeers
0
 
Éric MoreauSenior .Net ConsultantCommented:
something like this:

select TOP 5 *
from
     (select TOP 25 *
     from StatutImportation
     order by ID ASC) AS AA
order by ID DESC
0
 
johan_brohnCommented:

To get the N:th row

SELECT TOP 1 Column
FROM (SELECT TOP [N] Column
      FROM Table
      ORDER BY Column ) AS Alias
ORDER BY Column DESC

To get N:th thru M:th row sorted by Column

SELECT *
FROM (SELECT TOP [M - N + 1] Column
      FROM (SELECT TOP M Column
            FROM Table
            ORDER BY Column) AS Alias
      ORDER BY Column DESC) AS Alias
ORDER BY Column
0
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lozzamooreCommented:
You can also use a scalar query on the table using the ordered key to produce rownum like so:

select n1.*, (select count(id) from nthtest as n2 where n2.id<=n1.id) as rownum
from nthtest n1


This will probably run slow on big tables though.

Cheers,
0
 
Éric MoreauSenior .Net ConsultantCommented:
Any progress?
0
 
Éric MoreauSenior .Net ConsultantCommented:
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NetminderCommented:
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