Reading file value into variables

I am working on an old bookkeeping program who had to be modified because of the Euro.
I get fault results because some values are not read correctly.

Figures were dimensionned as double and than wroten to the file.

Example:

I read a correct 2 decimals file value:

Leverh.Agoed = 7309,34

When I assign it to a variable

Dim dGoederen as Double
dGoederen = Leverh.Agoed

dGoederen has the value: 7309,33984375

or with

Dim cGoederen as Currency
cGoederen = Leverh.Agoed

cGoederen now has a value of 7309,3398

Why those differences?
When I write 7309,34 to the file, I want the same value back when reading!

quintynAsked:
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Arthur_WoodConnect With a Mentor Commented:
sorry, didn't look closely enough at the original question.

The problem is that internal ALL numbers are stored in BINARY form, and MOST decimal fractions DO  NOT have an accurate BINARY representation:

Binary-------Decimal
0.1           0.5  = 1/2
0.01          0.25 = 1/4
0.001         0.125 = 1/8   and so on

But that means that 0.7 cannot be completely represented as a BINARY fraction

Not can 0.34.  The only choices are to use the Format Function, of the Round Function, to specify the number of decimal digits that you want to keep.  However, this is only a problem when values are DISPLAYED, as you want to keep the 4 digits of decimal accuracy (for Currency Values) when doing arithmetic, in your application.

Just control how the values are printed (or displayed) by means of the Format Function :

txtValue.Text = Format$(MyValue,"$#,###.00")  will "round" to two decimal digits when the value is displayed in the Text Box.

Arthur Wood
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simonbennettCommented:
Hi

The difference is due to decimal precision of each datatype. When writing.reading the values try coercing them to 2dp using the format or round functions

eg.

cGoederen = format(cGoederen,"0.00")

or

cGoederen = round(cGoederen,2)

Good Luck

Simon
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Arthur_WoodCommented:
rather than use Double for the Type of cGoederen , have you tried using Currency (which is a special case of Double)
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quintynAuthor Commented:
I think I understand now what the problem is.

Both of you gives more or less the same answer, but Arthur_Wood is more detailed. So I will give him the points.
I am sorry for simonbennett I can't split the points!

Anyway, thanks to both of you!

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quintynAuthor Commented:
Thanks again for the quick and good answer
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simonbennettCommented:
No problem

Glad it's sorted.

Simon
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