Solved

search for coded URL string "%06"

Posted on 2002-06-12
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Last Modified: 2010-03-31
I've got a decoded URL string, and in that string there is an not-displayable-character encoded representing "%06",
question is: How do search for that not displayable charcter where I want to use it as a delimiter in methods like StringTokenizer(String str, String delim)?
Thanks.
0
Comment
Question by:tomboman
5 Comments
 
LVL 16

Expert Comment

by:heyhey_
ID: 7074850
you can decode it first and then it will take a single char.
0
 
LVL 9

Expert Comment

by:Venci75
ID: 7074878
I don't think that you can use
String.indexOf() with such a character. Instead of this I suggest using
StringTokenizer(String str, String delim = "%06")
with the encoded string and after that - decoding the returned tokens
0
 
LVL 35

Expert Comment

by:girionis
ID: 7074979
 The following should work:

String s = "hello%06world";
java.util.StringTokenizer st = new java.util.StringTokenizer(s, "%06");
while (st.hasMoreTokens())
{
     System.out.println(st.nextToken());
}

  and the output should be:

hello
world

  Hope it helps.
0
 
LVL 19

Accepted Solution

by:
Jim Cakalic earned 50 total points
ID: 7076145
Unfortunately, that example will also treat all occurrences of any one of these characters as a delimiter. This is because the delim argument to StringTokenizer really specifies a set of characters that act as delimiters, not a single group of characters that must be completely matched.

In a recent JavaWorld article that discussed this 'pitfall' (http://www.javaworld.com/javaworld/jw-09-2000/jw-0922-javatraps_p.html) the following code solution was given as an alternative:

public static String[] tokenize(String input, String delimiters, boolean delimiterAsGroup) {
    Vector v = new Vector();
    String toks[] = null;

    if (!delimiterAsGroup) {
        StringTokenizer t = new StringTokenizer(input, delimiters);
        while (t.hasMoreTokens())
            v.addElement(t.nextToken());
    } else {
        int start = 0;
        int end = input.length();

        while (start < end) {
            int delimIdx = input.indexOf(delimiters,start);
            if (delimIdx < 0) {
                String tok = input.substring(start);
                v.addElement(tok);
                start = end;
            } else {
                String tok = input.substring(start, delimIdx);
                v.addElement(tok);
                start = delimIdx + delimiters.length();
            }
        }
    }

    int cnt = v.size();
    if (cnt > 0) {
        toks = new String[cnt];
        v.copyInto(toks);
    }
     
    return toks;
}

Best regards,
Jim Cakalic
0
 

Author Comment

by:tomboman
ID: 7077457
Very detailed answer jim, thanks.
0

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