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To Excecute an application from jar file

I have a jar file (xyz.jar) with

a1.class
a2.class
a3.class
a4.class
in which a1.class is a main class having
public static void main(String[] args)

in my manifest file i have included
Main-Class: a1.class

Now the problem is how to execute this application from the jar file directly.
This jar file is in c:\abc directory

Venci75

try
java -jar c:\abc\JarName.jar

umaiyer

ASKER

i tried with the same command

I am getting this error:

Exception in thread "main" java.util.zip.ZipException: The system cannot find the file specified
at java.util.zip.ZipFile.open(Native Method)
at java.util.zip.ZipFile.<init>(ZipFile.java:112)
at java.util.jar.JarFile.<init>(JarFile.java:117)
at java.util.jar.JarFile.<init>(JarFile.java:55)

Can u just let me know what's the problem

Thanks in advance.

Venci75

aha - the main class should be specified as a class name - not as a file name, that contain this class:
Main-Class: a1

umaiyer

ASKER

if this jar file(jarname.jar) is dependend on another jar file (comm.jar),do i have to include that jar file name in the manifest file of jarname.jar. if so how can i do this

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Venci75

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umaiyer

ASKER

i have included all the jar files that are required by the application which is in jarname.jar

in the Class-Path: x1.jar x2.jar etc.......

this application also uses one xml file which is outside the jar file.This application loads the contents of the xml file.
do i have to include this xml file in the manifest file. if so how to include this resource.

the problem i am facing is.......

i have jar file & xml file in
c:\abc directory
if i go to c:\abc>java -jar jarname.jar
my application displays the contents xml file

if i give the command in this fashion
c:\>java -jar "c:\abc\jarname.jar"
my application does not displays the details of xml file

how to come across this problem. is there a way to come out of this
Thanks in advance