Solved
Curves and x, y points
Posted on 2002-06-24
Hello everybody,
What I want is straightforward.
I need all the X, Y pairs of points of a quadratic curve.
For example I know the x1, y1 & x2, y2 and finally ctrX1 & ctrY1 points
to make the quadratic curve.
But I need to know the x,y points that this line is made of so I wil be able to
make an animation of an image up to this path. I itend not to draw the actual
line.
I found the PathIterator in the API but this does not really solve my problem.
From my understanding it reconstructs a complex shape with the aid of simpler ones.
It doesn't give any clues about the x,y points.
If I am wrong please tell me.
I found also a piece of code that I change it a bit to fit my needs. This will be
the worst solution though.
I cannot believe that for that simple problem I need to do the following. There must
be a simpler way.
What I found is to:
1. Make the curve
2. Take the Rectangle for that Shape with getBounds()
3. Make a smaller curve line
4. Take the rectangle for this as well
5. Subtract the areas (Not know how to do this)
6. Find the x, y points for the final area
Actually what I have just said is not the worst solution.
I thought somwthing even worst than this. :)
Anyway
I am not sure if this is possible.
What I have on hands is that foloowing code.
QuadCurve2D.Double q2d2 = new QuadCurve2D.Double( 10, 200, 95, 50, 200, 200);
r1 = q2d.getBounds2D().getBounds();
for (int x=0; x < r1.width; x++)
{
for (int y=0; y < r1.height; y++)
{
if (ar1.intersects(r1.x+x,r1.y+y,1,1)) // this point is on the arc
{
g2d.fillRect(r1.x + x, r1.y + y, 1, 1);
}
}
}
I do not know how to take the Area though form the previous shape.
Anybody can help me with some sample solution ???
Any comments ??
Other simpler ways ?
Do you thing I am in the right trck ?
Thank you in advance.