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FInd the repeating words in sequence

Posted on 2002-06-27
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Last Modified: 2010-04-15
I enter the sequence. for eg: ACTGCTACTG .

I need to find out the number of occurence of G and c in this string.

TIA
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Question by:kousis
7 Comments
 
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Expert Comment

by:dclaydon
ID: 7113219
Two methods

1) The systematic approach - start from one end and check each character one at a time for each character and keep counts of each letter

2) Recursive
utilise the function char* strstr(str1, str2) from stdio.h

returns a pointer to the first occurance of str2 (excluding the null terminator) within str1
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LVL 22

Expert Comment

by:cookre
ID: 7114457
Something like:

int NumG=0;
int NumC=0;
char *p;
char Target[256];

p=Target;
while (p<Target+strlen(Target))
      {
      if (*p=='G') NumG++;
      if (*p=='c') Numc++;
      p++;
      )
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Expert Comment

by:Triskelion
ID: 7115406
Is it always going to be full of characters?
Can there be numbers?
Will you ever do groups of words?
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Accepted Solution

by:
harrlow earned 150 total points
ID: 7115624
kousis,
Your example sequence looks like a gene sequence to me.
In that case, it's probably going to very long but would only consists of 4 different letters.

So, i think the system approach proposed by dclaydon is better because the recursive approach will be very resource intensive.
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LVL 10

Expert Comment

by:oleber
ID: 7116333
int CountLetter(char* strSource, char cMatch)
{
   int nCounter=0;
   for (;strSource != '\0';strSource++)
     if (*strSource == cMatch)
        nCounter++;
}
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Author Comment

by:kousis
ID: 7116413
yes. it's DNA sequence
thanx for ur reply
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Expert Comment

by:harrlow
ID: 7121768
Actually, i think the others contributed.
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