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Solved

Inherited x 2

Posted on 2002-06-27
6
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Last Modified: 2013-11-23
I'm well aware of how to call an overridden ancestor's method in the descendent class' implementation: Simply use the "inherited" keyword which will send the same parameters in the same order to the inherited ancestor method.

However, I have a situation where it would be best for a descendent class NOT to call the inherited method of its IMMEDIATE ancestor, but the method that was defined TWO classes ago!  How do I do this?
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Comment
Question by:Pummel
6 Comments
 
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Expert Comment

by:TOndrej
ID: 7114821
It's neither possible (without nasty hacks with VMT) nor really needed.
If you have such situation it usually means you need to redesign your class hierarchy.

Perhaps an acceptable quick workaround might be to implement the immediate ancestor's method to call the next ancestor's method based on a parameter or perhaps a property flag.
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Accepted Solution

by:
bes67 earned 134 total points
ID: 7115599
Try something like this:

Suppose you have following class hierarchy

type
  TSFn = function:Boolean of object;

  TGrandClass = class
  public
    function SomeFunction: Boolean; virtual;
  end;

  TBaseClass = class(TGrandClass)
  public
    function SomeFunction: Boolean; override;
  end;

  TSomeClass = class(TBaseClass)
  public
    function SomeFunction: Boolean; override;
  end;

and you want to call TGrandClass.SomeFunction from TSomeClass.SomeFunction without calling TBaseClassFunction. Well, here it is

function TSomeClass.SomeFunction: Boolean;
var gcq: TMethod;
begin
  gcq.Code := @TGrandClass.SomeFunction;
  gcq.Data := Self;
  Result := TSFn(gcq);
end;

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Expert Comment

by:Lee_Nover
ID: 7116171
interesting :)
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Expert Comment

by:kretzschmar
ID: 7118524
? what is tsfn()
0
 
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Expert Comment

by:Lee_Nover
ID: 7119382
type
 TSFn = function:Boolean of object;


so in the case above it's a cast :)
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LVL 27

Expert Comment

by:kretzschmar
ID: 7119670
oops, overread this declaration,
thanks lee for pointing out

meikl ;-)
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