We value your feedback.
Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!
Course Of The Month
8 days, 3 hours left to enrollBecome a Premium Member and unlock a new, free course in leading technologies each month.
Solved
How do I setup a "onClick" event without using the object inspector?
Posted on 2002-06-28
I have a form that has 56 charts on it. I defined the charts as an array and set the properties in the code snippet below:
var
TestProgressForm: TTestProgressForm;
Charts : array[1..MAX_WFR_COL,1..MA
Procedure TTestProgressForm.AssignCh
var col,row : integer;
ChartSeries : TChartSeries;
begin
for col := 1 to MAX_WFR_COL do begin
for row := 1 to MAX_WFR_ROW do begin
Charts[col,row] := Tchart.Create(TestProgress
Charts[col,row].Parent := TestProgressForm;
BarSeries[col,row] := TBarSeries.Create(self);
Charts[col,row].AddSeries(
charts[col,row].Enabled := TRUE;
charts[col,row].Width := 80;
charts[col,row].Height := 80;
{set up properties here}
charts[col,row].Top := 15 + (row-1)*(charts[col,row].H
charts[col,row].Left := 55 + (col-1)*(charts[col,row].W
with charts[col,row].Series[0] as TBarSeries do begin
Clear;
CustomBarWidth := 10;
title := '';
Marks.Visible := FALSE;
ColorEachPoint := True;
Marks.Style := smsPercent;
Visible := False ;
ShowInLegend := False;
AutoMarkPosition := False;
HorizAxis := aBottomAxis;
VertAxis := aLeftAxis;
end;
end;
end;
end;
What I would like to do is set up the code so that when I click or double click on the chart a new form is displayed showing the details. The new form would be called TestDetails and would need to know which chart was double clicked on. I do not how to go about defining this.
Thank you,
p
var
TestProgressForm: TTestProgressForm;
Charts : array[1..MAX_WFR_COL,1..MA
Procedure TTestProgressForm.AssignCh
var col,row : integer;
ChartSeries : TChartSeries;
begin
for col := 1 to MAX_WFR_COL do begin
for row := 1 to MAX_WFR_ROW do begin
Charts[col,row] := Tchart.Create(TestProgress
Charts[col,row].Parent := TestProgressForm;
BarSeries[col,row] := TBarSeries.Create(self);
Charts[col,row].AddSeries(
charts[col,row].Enabled := TRUE;
charts[col,row].Width := 80;
charts[col,row].Height := 80;
{set up properties here}
charts[col,row].Top := 15 + (row-1)*(charts[col,row].H
charts[col,row].Left := 55 + (col-1)*(charts[col,row].W
with charts[col,row].Series[0] as TBarSeries do begin
Clear;
CustomBarWidth := 10;
title := '';
Marks.Visible := FALSE;
ColorEachPoint := True;
Marks.Style := smsPercent;
Visible := False ;
ShowInLegend := False;
AutoMarkPosition := False;
HorizAxis := aBottomAxis;
VertAxis := aLeftAxis;
end;
end;
end;
end;
What I would like to do is set up the code so that when I click or double click on the chart a new form is displayed showing the details. The new form would be called TestDetails and would need to know which chart was double clicked on. I do not how to go about defining this.
Thank you,
p
[X]
Welcome to Experts Exchange
Add your voice to the tech community where 5M+ people just like you are talking about what matters.
- Help others & share knowledge
- Earn cash & points
- Learn & ask questions
2 Comments
Hi,
1. In your form declaration add a new procedure declaration:
type
TTestProgressForm =
...
public
...
procedure ChartsClick(Sender: TObject); // common to all charts clicks
...
end;
2. Write that procedure in the 'implementation' section
procedure TTestProgressForm.ChartsCl
begin
if (Sender is TChart) then begin
// Assign the chart to a property of TestDetails form
TestDetails.TheChart := (Sender as TChart);
// Show the form
TestDetails.Show;
end;
end;
3. Add next line somewhere in your loop above (when creating the charts:
// This line assigns ChartsClick procedure as OnClick event handler (their declarations must be the same)
charts[col,row].OnClick := ChartsClick;
4. In TestDetails form:
TestDetails =
private
FChart: TChart; // new private field
....
public
property TheChart: TChart read FChart write FChart; // new public property to hold a reference to a chart
...
end;
Now, in the events of TestDetails form you can use 'TheChart' to obtain a reference to the chart that has been clicked last. For example:
with TheChart.Series[0] as TBarSeries do begin
...
end;
Perhaps there is an easier way but that's coming up in my mind now and it's almost 5 AM here. If you need more info, please ask.
Regards, Geo
1. In your form declaration add a new procedure declaration:
type
TTestProgressForm =
...
public
...
procedure ChartsClick(Sender: TObject); // common to all charts clicks
...
end;
2. Write that procedure in the 'implementation' section
procedure TTestProgressForm.ChartsCl
begin
if (Sender is TChart) then begin
// Assign the chart to a property of TestDetails form
TestDetails.TheChart := (Sender as TChart);
// Show the form
TestDetails.Show;
end;
end;
3. Add next line somewhere in your loop above (when creating the charts:
// This line assigns ChartsClick procedure as OnClick event handler (their declarations must be the same)
charts[col,row].OnClick := ChartsClick;
4. In TestDetails form:
TestDetails =
private
FChart: TChart; // new private field
....
public
property TheChart: TChart read FChart write FChart; // new public property to hold a reference to a chart
...
end;
Now, in the events of TestDetails form you can use 'TheChart' to obtain a reference to the chart that has been clicked last. For example:
with TheChart.Series[0] as TBarSeries do begin
...
end;
Perhaps there is an easier way but that's coming up in my mind now and it's almost 5 AM here. If you need more info, please ask.
Regards, Geo
I think it would be easier just to use some determining code in the OnClick handler... like this:
if (Sender as TChart).Name = "Chart1" then...
If there is position information, where you can determine
which chart is being accessed by it's X and Y coordinates, you can do that too, like
ChartID : integer;
ChartID = Idfunc((Sender as TChart).Left,(Sender as TChart).Bottom);
Where IDfunc returns the index as a function of left and right.
Finally, if you use the tag field when you create, putting in the number of the chart, then you can just do this:
...during creation of the charts
Charts[col,row].tag = col*100+row;
...during the OnClick
switch(Sender as TChart).tag)
...
if (Sender as TChart).Name = "Chart1" then...
If there is position information, where you can determine
which chart is being accessed by it's X and Y coordinates, you can do that too, like
ChartID : integer;
ChartID = Idfunc((Sender as TChart).Left,(Sender as TChart).Bottom);
Where IDfunc returns the index as a function of left and right.
Finally, if you use the tag field when you create, putting in the number of the chart, then you can just do this:
...during creation of the charts
Charts[col,row].tag = col*100+row;
...during the OnClick
switch(Sender as TChart).tag)
...
Featured Post
Question has a verified solution.
If you are experiencing a similar issue, please ask a related question
A lot of questions regard threads in Delphi.
One of the more specific questions is how to show progress of the thread.
Updating a progressbar from inside a thread is a mistake.
A solution to this would be to send a synchronized message to the…
Have you ever had your Delphi form/application just hanging while waiting for data to load?
This is the article to read if you want to learn some things about adding threads for data loading in the background.
First, I'll setup a general applica…
Monitoring a network: why having a policy is the best policy? Michael Kulchisky, MCSE, MCSA, MCP, VTSP, VSP, CCSP outlines the enormous benefits of having a policy-based approach when monitoring medium and large networks. Software utilized in this v…
In this video you will find out how to export Office 365 mailboxes using the built in eDiscovery tool. Bear in mind that although this method might be useful in some cases, using PST files as Office 365 backup is troublesome in a long run (more on t…
Suggested Courses
Earn Certification
HTML5 Specialist - Certification
Free withPremium
Course of the Month8 days, 3 hours left to enroll
Earn Certification
CompTIA IT Fundamentals
$49.00$44.10
617 members asked questions and received personalized solutions in the past 7 days.
Join the community of 500,000 technology professionals and ask your questions.