Dynamic Control Creation

Posted on 2002-07-02
Last Modified: 2010-04-15
I would like to dynamically load a control, a control that I don;t know of at desgin-time.
In VB6 there was a Controls.Add were u suplied a ClsID and the control was loaded.
There must be something like this in C#, a way to load at run-time a dll with a UserControl in it and be able to put it on screen.
Question by:Azmodan
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Accepted Solution

kpkp earned 50 total points
ID: 7124230
sounds like you need to use the Activator.CreateInstance method...

check out

Author Comment

ID: 7124675
yes.this seems to be the way to go, but i couldn;t make it work


raises an exception:  File or assembly name C:\Simplex.dll, or one of its dependencies, was not found.

what am i doing wrong?

Expert Comment

ID: 7124705
Are you including a refernce to simplex.dll in your project (or including it in the csc command if you're not using  You need to do this - or register simplex.dll in the GAC.
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Author Comment

ID: 7124739
No,thats the whole point... to load a control at runtime!!

So, just with code, not by adding it to the references at design-time.

Can this be done without the GAC? By giving it the Asembly, or adding it's reference at run time...


Expert Comment

ID: 7124917
If your assembly that you want to use dynamically isn't in the GAC, then it must be in the same directory as the calling application.  Also - don't include the path or .dll extension in the CreateInstance() call.

Author Comment

ID: 7126341
yeah..that seams to work. If i don't put the .dll in its name, it takes it from the current directory.

But... the CreateInstance returns an object or ObjectHandle. If I want to put the loaded control on the form, I need to use Controls.Add... which takes a Windows.Forms.Control. And the system won;t cast object to control. Is there a way?

Author Comment

ID: 7126351
no..i got it
ObjectHandle.Unwrap.. returns a castable pointer. And it can be casted to Forms.Control

Author Comment

ID: 7126473

i'll figure out the details

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