Solved

SHELL TO OPEN A FOLDER

Posted on 2002-07-16
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Last Modified: 2010-05-03
hi there,
Whats to code to open an existing folder.

I want to open app.path & "\distribution"

How to open it and only showing *.zip files..

Thanks..
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Question by:pfjvisser
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10 Comments
 
LVL 22

Expert Comment

by:rspahitz
ID: 7157622
One simple way:

dim strFilename as string

strFilename = dir$(app.path & "\distribution\*.zip")
while strFilename <> vbNullString
  'Pick one of the follow output choices or others

  ' Option to add filename to a list control
  List1.AddItem strFilename

  ' option to display filename in the immediate window
  Debug.print strFilename

  ' option to add filename to a blank textbox
  Text1.text = Text1.text & strFilename & vbCrLf

  strFilename = dir$
wend
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Author Comment

by:pfjvisser
ID: 7157770
Thanks  rspahitz
But i meen to open it in the windows explorer.
I hoop you can give me a sulution..

Gr,
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LVL 22

Expert Comment

by:rspahitz
ID: 7157782
Are you talking about the open dialog box?

If you don't have it, add the component (Microsoft Common Dialog Control) to your project.

Set the filter property= "zip files (*.zip)|*.zip|All files (*.*)|*.*"

In code, set the filename property = "app.path & "\distribution\*.zip"

Then launch the window.

In code:

CommonDialog1.Filter = "zip files (*.zip)|*.zip|All files (*.*)|*.*"
CommonDialog1.Filename = "app.path & "\distribution\*.zip"
CommonDialog1.ShowOpen

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Author Comment

by:pfjvisser
ID: 7157787
Whel almost.

-"Distributie" = FOLDERNAME TO OPEN IN EXPLORER-
I meen like a shell(app.path & "\distributie\")

Thats when the windows explorer op the path..

Gr.
0
 

Author Comment

by:pfjvisser
ID: 7157813
Whel almost.

-"Distributie" = FOLDERNAME TO OPEN IN EXPLORER-
I meen like a shell(app.path & "\distributie\")

Thats when the windows explorer op the path..

Gr.
0
 
LVL 28

Expert Comment

by:vinnyd79
ID: 7158038
you could use this,but I don't know about only showing zip files:

Private Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As Long, ByVal _
lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, _
ByVal nShowCmd As Long) As Long
Private Const SW_SHOWNORMAL = 1

Public Sub OpenDirectory(Directory As String)
ShellExecute 0, "Open", Directory, vbNullString, vbNullString, SW_SHOWNORMAL
End Sub

Private Sub Command1_Click()
OpenDirectory (App.Path & "\distribution")
End Sub
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LVL 28

Accepted Solution

by:
vinnyd79 earned 50 total points
ID: 7158059
actually you can just use it like this without the OpenDirectory Sub:

Private Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As Long, ByVal _
lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, _
ByVal nShowCmd As Long) As Long
Private Const SW_SHOWNORMAL = 1

Private Sub Command1_Click()
ShellExecute 0, "Open", App.Path & "\distribution", vbNullString, vbNullString, SW_SHOWNORMAL
End Sub
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LVL 16

Expert Comment

by:Richie_Simonetti
ID: 7158076
IMHO, there is no way you could "filter" an Explorer window.
You have to do it by yourself (code from rspahitz could help).
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LVL 22

Expert Comment

by:rspahitz
ID: 7158122
The old versions of explorer let you filter, but that caused lots of problems because every folder would filter with the same criteria and it caused a lot of confusion if you left and came back later...you'd think that your files were gone.  For example, you filter by *.zip, then look for your Word documents and can't find them.

What you might want to do is simply drop a filelistbox (looks like a piece of paper with a folded corner) on your form and add that filter in the view by changing the Pattern property to "*.zip"  I think you also need to change the "current" directory to the desired directory in code:

CurDir = app.path & "\distribution"


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Author Comment

by:pfjvisser
ID: 7159092
Thanks all. I had solved the prob with the coding from
vinnyd79. SO thanks to al of you folks..
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