Export Soft Copy to local drive Via Crystal Report 7.0

I'm using VB 5.0, Crystal Report 7.0, running on Win 2K.
My Database is SQL 6.5.

Here, I have a ready made report at my c:\ called MyRpt.rpt

I'd wish to export the report to another format thru my VB 5.0. Anybody can illustrate me the steps?

With CrystalReport1
  .ReportFileName = "c:\MyRpt.rpt"
  .ReplaceSelectionFormula "{view_rpt_My_Report.id} = 4094"
  .Destination = crptToFile
  .PrintFileType = crptText
  .PrintFileName = "MyFile.txt"
  .PrintReport
End With

I've got the error msg -> "can't open SQL Server"

Pls help.. how to overcome this? Where shall I supply my Database connection, etc?

thanks.
my8817Asked:
Who is Participating?
 
ianouiiConnect With a Mentor Commented:
'Place a Crystal Report control on your form by choosing
'from the component on the toolbox.

'Put this code in.

Screen.MousePointer = vbHourglass

With CrystalReport1
  .Connect = "DSN=UsrDSN; UID=sa; PWD=pswd"
  .ReportFileName = "c:\MyRpt.rpt"
  .ParameterFields(0) = "prmProcessNo;4094;TRUE"
  .Destination = crptToFile
  .PrintFileType = crptText
  .PrintFileName = "c:\Test.txt"
  .Action = 1
End With

Screen.MousePointer = vbDefault

'Define your DSN nicely then to ensure your db connection is hassle free.
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my8817Author Commented:
the error msg was together with this
Run-Time error '20599'.

pls help.. quite urgent.
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my8817Author Commented:
left out some lines of code.

With CrystalReport1
 .LogOnServer "p2smon.dll", "DBSvr", "MyDb", "SA", "Pswd"
 .ReportFileName = "c:\MyRpt.rpt"
 .ReplaceSelectionFormula "{view_rpt_My_Report.id} = 4094"
 .Destination = crptToFile
 .PrintFileType = crptText
 .PrintFileName = "MyFile.txt"
 .Action = 1
 .PrintReport
End With

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my8817Author Commented:
rite now, another error encountered.

-----------------------------------------------------------
Run-Time error '20515'

Error in formula <Record_Selection>.
'{tblA.EffectiveDt} in {tblB.EffetiveDt} to {tblB.CeaseDt} and'

This field name is not known.

-----------------------------------------------------------

pls help.. thanks.
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mlmccCommented:
Looks like there is more to the selection formula but as a guess if what you gave is accurate

'{tblA.EffectiveDt} in {tblB.EffetiveDt} to {tblB.CeaseDt} and'

should be (missing c in the second tblB.EffectiveDt)

'{tblA.EffectiveDt} in {tblB.EffectiveDt} to {tblB.CeaseDt} and'

mlmcc
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my8817Author Commented:
ok, here's the senario. I have an existing report which I can use the Crystal Report designer to call to DB without any problem by supplying only 1 parameter.

in that case, do I still need to pass more than 1 parameter to the VB App?
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mlmccCommented:
No you shouldn't need more than 1.

mlmcc
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my8817Author Commented:
mlmcc,

ok, I've no idea how to proceed with this. Can u pls just supply me the complete coding for VB to export my existing report to another format?

Just drop all my code above. Thanks.
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my8817Author Commented:
paste my latest code here.

Dim cr_Export_App As New CRPEAuto.Application
Dim cr_Export_Rpt As CRPEAuto.Report

With cr_Export_App
     .LogOnServer "p2smon.dll", "UsrDSN", "MyDB", _
                  "sa", "pswd"
     Set cr_Export_Rpt = .OpenReport("c:\MyRpt.rpt", crOpenReportByTempCopy)

End With

With cr_Export_Rpt

    .ReadRecords
    .ExportOptions.FormatType = crEFTText
    .ExportOptions.DestinationType = crEDTDiskFile
    .ExportOptions.DiskFileName = "c:\Test.txt"
    .ReplaceSelectionFormula "{prmProcessNo} = 4094"
    .Export False
End With

I encountered the error at the .ReadRecords
says

Run-Time error '20599'
can't open SQL Server

Pls help me to verify it, ok?

I've checked on my System DSN, it's definitely there.
Btw, is my coding syntax & the logic flow correct?
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my8817Author Commented:
Thanks! This really solved my problem.
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