Want to protect your cyber security and still get fast solutions? Ask a secure question today.Go Premium

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 238
  • Last Modified:

How do you reset an array afyer you've used it??

Hi,

I'm reading in a different set of values to a 2D Array continuosly from an image that will then be put into a 1D Array. For each instance of the 1D Array I want to do certain calculations and then I want to reset the array so that the next batch of 2D Array values being read in can be inserted into the 1D Array. How do I reset an array?? Below is the section of code where I'm trying to do this. At the moment when I compile the program I get an error message saying 'ArrayIndexOutOfBoundsException' at the line:
copy[x] = sum;

Here is the section of code:

public void filter(int[][] template) {
 
       
  IntImage src = new IntImage(ImageSize, ImageSize);
  src = imageIn;
       
  int nMaskRows = template.length;
  int nMaskCols = template[0].length;
       
  int rBorder = nMaskRows / 2;  // integer division
  int cBorder = nMaskCols / 2;
  int sum;
  int[] copy = new int[nMaskRows*nMaskCols];//1D Array
  int x = 0;
 
  for (int r = 0; r < (ImageSize - nMaskRows + 1); r++) {
    for (int c = 0; c < (ImageSize - nMaskCols + 1); c++) {
    sum = 0;
    for (int mr = 0; mr < nMaskRows; mr++) {
      for (int mc = 0; mc < nMaskCols; mc++) {
      sum = imageIn.pixels[r+mr][c+mc] * template[mr]    [mc];//getting the result value
      copy[x] = sum;  //<==ArrayIndexOutOfBoundsException
at this line
      ++x;

      }//for mc
    }//for mr
             
   sort(copy); // sorting the 1D Array
   imageOut.pixels[r+rBorder][c+cBorder] = median(copy);
//setting the output pixel to be the median
       THIS IS WHERE I WANT TO RESET THE ARRAY 'copy[]'?
 }//forc
}//forr
       
  display(imageIn, imageOut);
  }//filter
     
Regards,
Guster

0
Guster
Asked:
Guster
  • 2
1 Solution
 
iDebCommented:
1. The ArrayOutOfBounds Exception is happening becuause you are not setting x =0 after the loop
 for (int mr = 0; mr < nMaskRows; mr++) {
     for (int mc = 0; mc < nMaskCols; mc++) {
          ...........
          ...........
     }
  }

  x = 0;

2. You need not reset the array. If you insist, use a double for loop to initialize the individual element s of the array to 0;
0
 
delphi3Commented:
Guster,
Insert a System,out.println(x) below
     copy[x] = sum;  //<==ArrayIndexOutOfBoundsException
at this line
     ++x;

as this:

     copy[x] = sum;  //<==ArrayIndexOutOfBoundsException
at this line
     System,out.println(x);
     ++x;



x may be either near zero, or it may be extremely large and exceed the capacity of the array that you set earlier.

Delphi3
0
 
delphi3Commented:
oops a typo in that

System.out.println(x);

Delphi3
   
0

Featured Post

Hire Technology Freelancers with Gigs

Work with freelancers specializing in everything from database administration to programming, who have proven themselves as experts in their field. Hire the best, collaborate easily, pay securely, and get projects done right.

  • 2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now