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Searching the whole word in the text box

Maybe anybody have a procedure ,how to search a whole word in the text box .

The same functionality like Ctrl F (Whole word only)

Best regards,
Irina
0
irina_1973
Asked:
irina_1973
1 Solution
 
adam8Commented:
Hi,
I developed a search function for you. I have checked it but there still may be bugs.

'HERE IT IS
Option Explicit
Dim ePos As Long, sPos As Long

Function FindWord(SearchWord As String, TextBoxA As TextBox, Optional StartPosition As Long = 0, Optional CaseSensitive As Boolean = False) As Boolean
    Const Chars = "0123456789abcdefghijklmnopqrstuvwxyz"
    Dim i As Long
    Dim a As Integer, b As Integer
    Dim Search As String, TBox As String
   
    If Trim$(SearchWord) <> SearchWord Then
        MsgBox "You can not search for whole words while you search time has more than one word."
        FindWord = False
        GoTo NoMatch
    End If
   
    Search = SearchWord
    TBox = TextBoxA
   
    FindWord = False
    ePos = 0
    sPos = StartPosition
    i = 0
    If CaseSensitive = False Then Search = LCase$(Search): TBox = LCase$(TBox)
   
    Do
        i = i + 1
        i = InStr(i, TBox, Search)
        If i = 0 Then GoTo NoMatch
       
        If i > 0 Then
            sPos = i
            ePos = i + Len(Search)
           
            If sPos - 1 > 0 Then
                a = InStr(1, Chars, Mid$(LCase$(TBox), sPos - 1, 1))
            Else
                a = 0
            End If
           
            If ePos > Len(TBox) Then
                b = 0
            Else
                b = InStr(1, Chars, Mid$(LCase$(TBox), ePos, 1))
            End If
           
            If a = 0 And b = 0 Then
                i = 0
                FindWord = True
            End If
        End If
       
    Loop Until i = 0
   
Exit Function
NoMatch:
sPos = 0
ePos = 0
FindWord = False
End Function


<<<<<<<<<<<THIS IS AN EXAMPLE OF HOW TO USE IT>>>>>>>>

Private Sub Command1_Click()
    Dim ret As Boolean
    ret = FindWord("", Text1)
   
    If ret = True Then
        'Select the text that the user searched for.
        Text1.SelStart = sPos - 1
        Text1.SelLength = ePos - sPos
        Text1.SetFocus
       
    Else
        MsgBox "No match string was found"
    End If
End Sub

If you need me to send you the sample project I made please let me know. If there are any bugs please let me know.
0
 
adam8Commented:
By the way I will quickly explain how the use the function..

Function FindWord(SearchWord As String, TextBoxA As TextBox, Optional StartPosition As Long = 0, Optional CaseSensitive As Boolean = False) As Boolean

The search Word is what word you want to look for.

the TextBoxA is the text box you want to search in.

the Startposition is the spot in the text box you want to start searching from (21 would mean 21 characters from the start)

CaseSensitive explains itself.


There is one error I found in the code. I forgot to fix it before i submitted it.

In the Main search function where you have the following code.

   sPos = StartPosition
   i = 0

   CHANGE IT TO .....

    sPos = 0
    i = StartPosition - 1
0
 
yongyihCommented:
try this:

Dim SearchString, SearchChar, MyPos
SearchString ="XXpXXpXXPXXP"   ' String to search in.
SearchChar = "P"   ' Search for "P".

' A textual comparison starting at position 4. Returns 6.
MyPos = Instr(4, SearchString, SearchChar, 1)  

' A binary comparison starting at position 1. Returns 9.
MyPos = Instr(1, SearchString, SearchChar, 0)

' Comparison is binary by default (last argument is omitted).
MyPos = Instr(SearchString, SearchChar)   ' Returns 9.

MyPos = Instr(1, SearchString, "W")   ' Returns 0.

hope this can help you. good luck. ^_^
0
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jayeshshahCommented:
more better you can use the instring function as below

if instr(1,"String1",String2 & " ")>0 then
  Msgbox "Word found"
else
  Msgbox "Word could not be located"
end if
0
 
adam8Commented:
My search routine is similar to doing a "Find whole words only" search in Microsoft Office. It will only return a match if the exact search term is found in the textbox. If there is a full stop or comma after the word my search function will take that into account as well, unlike the other examples posted here so far.

example:

Text1 = "hello, how are you?"

If you did a search for "Hello" with my search function it would take the comma after the hello into account. The comma doesn't alter the word hello.
0
 
adam8Commented:
I noticed a few errors in my previous search function.

Instead of using the first one I posted use this one.

Option Explicit
Dim ePos As Long, sPos As Long

Function FindWord(SearchWord As String, TextBoxA As TextBox, Optional StartPosition As Long = 1, Optional CaseSensitive As Boolean = False) As Boolean
    Const Chars = "0123456789abcdefghijklmnopqrstuvwxyz"
    Dim i As Long
    Dim a As Integer, b As Integer
    Dim Search As String, TBox As String
   
    If Trim$(SearchWord) <> SearchWord Then
        MsgBox "You can not search for whole words while you search time has more than one word."
        FindWord = False
        GoTo NoMatch
    End If
   
    Search = SearchWord
    TBox = TextBoxA
   
    FindWord = False
    ePos = 0
    sPos = 0
    i = StartPosition - 1
   
    If CaseSensitive = False Then Search = LCase$(Search): TBox = LCase$(TBox)
   
    Do
        i = i + 1
        i = InStr(i, TBox, Search)
        If i = 0 Then GoTo NoMatch
       
        If i > 0 Then
            sPos = i
            ePos = i + Len(Search)
           
            If sPos - 1 > 0 Then
                a = InStr(1, Chars, Mid$(LCase$(TBox), sPos - 1, 1))
            Else
                a = 0
            End If
           
            If ePos > Len(TBox) Then
                b = 0
            Else
                b = InStr(1, Chars, Mid$(LCase$(TBox), ePos, 1))
            End If
           
            If a = 0 And b = 0 Then
                i = 0
                FindWord = True
            End If
        End If
       
    Loop Until i = 0
   
Exit Function
NoMatch:
sPos = 0
ePos = 0
FindWord = False
End Function
0
 
irina_1973Author Commented:
Thank you ,adam8!
You helped me a lot .
Thanks you that you free you time to write it .

Also ,thanks to yongyih, jayeshshah.
It's also very useful information for me .
0
 
adam8Commented:
Thank you for accepting my answer,

remember to use the newest function that I posted which is the one I fixed up a few problems with.
0

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