asked on

integer subtotals

problem.
need to read numerical data from text file.
Maybe using
while(fscanf(fp,"%d%d%d",&num1,&num2,&num3)!=EOF)
eg. num1 num2 num3 num4
2 3 * 4 = 12
2 6 * 4 = 24
--
4 6 * 3 = 18
4 6 * 7 = 42
--
5 6 * 3 = 18
5 5 * 2 = 10
--
as you can see num2 is multiplied by num3 to give
an answer of num4.
Using num1 to control the addition I need to sub total
the num4s ie.12+4=36, 18+42=60, 18+10=28.
and display each sub total between the different
num1s. Then display the grand total of all sub totals
at the end.
Can anyone help?

imladris

Would something like:

int num1,num2,num3,num4;

while(fscanf(fp,"%d%d%d",&num1,&num2,&num3)!=EOF)
{ num4=num2*num3;
printf("%d %d * %d = %d\n",num2,num2,num3,num4);
fscanf(fp,"%d%d%d",&num1,&num2,&num3);
num4+=num2*num3;
printf("%d %d * %d = %d\n",num1,num2,num3,num2*num3);
printf("%d\n",num4);
}

Do what you're after?

If not, please clarify.

mitziro

ASKER

sorry I may not have been very clear in my question.
The num1s are just markers. When a change in marker
value is detected then that should trigger a sub total.
(num2*num3)
When num1s have been read in as say any value, when
a num1 value is detected greater than the one previously
read then because the value of num1 changes it should
trigger a control break.
Bear in mind that the amount and value of num1s could be
any.

ASKER CERTIFIED SOLUTION

imladris

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obg

int sum, num1, num2, num3, num4, tot, i;
i = sum = tot = 0;
while (fscanf(fp, "%d %d %d", &num1, &num2, &num3) != EOF) {
if (num1 != i && sum != 0) {
printf("Sum for %d = %d\n", i, sum);
tot += sum;
sum = 0;
}
i = num1;
num4 = num2 * num3;
printf("%d %d * %d = %d\n", num1, num2, num3, num4);
sum += num4;
}
tot += sum;
printf("Sum for %d = %d\nTotal = %d\n", i, sum, tot);

... Well, it turned out almost the same I guess.

jmcg

Nothing has happened on this question in more than 13 months. It's time for cleanup!

My recommendation, which I will post in the Cleanup topic area, is to
accept answer by imladris.

PLEASE DO NOT ACCEPT THIS COMMENT AS AN ANSWER!

jmcg
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