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you would need to enumerate all running processes and look at the module filename to determine which is the process you are interested in. you do have a problem if more than once instance is running...<br />
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what platform are you on?
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you would need to enumerate all running processes and look at the module filename to determine which is the process you are interested in. you do have a problem if more than once instance is running...

what platform are you on?

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Dear expert(s),

A request has been made to close this Q in CS:
https://www.experts-exchange.com/questions/20442410/Clean-up-the-questions.html [https://www.experts-exchange.com/questions/20442410/Clean-up-the-questions.html]

Without a response in 72 hrs, a moderator will finalize this question by:

 - Saving this Q as a PAQ and refunding the points to the questionner

When you agree or disagree, please add a comment here.

Thank you.

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<div class="content wysiwyg-content">
hi,<br />
<br />
My doubt is as follows.<br />
Let us suppose a program(prgm 1) is executing in an infinite while loop. Now from another program (prgm 2) we should get the process id of prgm 1 which is already executing.
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hi,

My doubt is as follows.
Let us suppose a program(prgm 1) is executing in an infinite while loop. Now from another program (prgm 2) we should get the process id of prgm 1 which is already executing.

getProcessid( one program from another program);

C is a general-purpose, imperative computer programming language, supporting structured programming, lexical variable scope and recursion, while a static type system prevents many unintended operations. By design, C provides constructs that map efficiently to typical machine instructions, so it has found lasting use in applications that had formerly been coded in assembly language, including operating systems as well as various application software for computers ranging from supercomputers to embedded systems. It is distinct from C++ (which has its roots in C) and C#, and many later languages have borrowed directly or indirectly from C.