stable marriage problem

I'm struggling to get the stable marriage problem solved in java. I have two arrays of point3d's and have a list of all the possible distances in rank order, but i can't get the algorithm to work. Can any1 help please
Cheers
n0152974Asked:
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CEHJCommented:
Please post your code so far
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n0152974Author Commented:
   public void stableMarriage()
    {
        AvailableIndex [] startAvailableIndex = new AvailableIndex[start.length];
        for(int b = 0; b < startAvailableIndex.length; b++)
        {
            startAvailableIndex[b] = new AvailableIndex();
        }
        while(!allPaired(startAvailableIndex))
        {
               System.out.println("in while loop");
            //pick 1st unpaired
            int i = 0;
            for(i=0;i<start.length;i++)
            {
                if(startAvailableIndex[i].index() == -1)
                {
                    break;
                }
               
            }
               PointDist temp;
               if(startAvailableIndex[i].index == -1)
               {
                 temp = lists[i][0]; //get first choice
               }
               else
               {
                    temp = lists[i][startAvailableIndex[i].index()];
               }
               startAvailableIndex[i].increment();
            //remove lists[i][0] and shift then all down
               System.out.println("temp "+temp.toString());
            if(temp.available()==true)
            {
                    System.out.println(temp.toString());
                if(temp.dist() <= start [i].distance( end[startAvailableIndex[i].index()] )  )
                {
                    //makePair(start[i],temp);
                         startAvailableIndex[i].available = false;
                }
                    else
                    {
                         //remain unpaired
                         //startAvailableIndex[i] = -1;
                    }              
            }
        }
          for(int b = 0; b < startAvailableIndex.length; b++)
        {
            System.out.println(startAvailableIndex[b].index());
        }
    }
   
    public boolean allPaired(AvailableIndex [] temp)
    {
          System.out.println("All paired");
        for(int b = 0; b < temp.length; b++)
        {
            if(temp[b].available() == true)
            {
                return false;
            }
        }
        return true;
    }
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n0152974Author Commented:
AvailableIndex is a class containing a boolean representing available, int (index) and float (distance)
0
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danBoshCommented:
all you need to do is bosh
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n0152974Author Commented:
any other constuctive comments please?
0
n0152974Author Commented:
is it possible for me to do this problem or is another way needed?
0
n0152974Author Commented:
can any1 help me please?
0
CEHJCommented:
0
SpideyModCommented:
A request for refund has been made.  Experts you have 72 hours to respond.

danBosh,
I have seen many of your responses that say "all you need to do is bosh".  If you have nothing professional or constructive to add to a question, do not post.  This will be your only warning.

SpideyMod
Community Support Moderator @Experts Exchange
0
danBoshCommented:
Sorry SideyMod, n0152974 is my flatmate, and the comment was only a joke
0
danBoshCommented:
Sorry SideyMod, n0152974 is my flatmate, and the comment was only a joke
0
SpideyModCommented:
danBosh,
Thanks for responding.

SpideyMod
Community Support Moderator @Experts Exchange
0
SpideyModCommented:
PAQ'd and points refunded.

SpideyMod
Community Support Moderator @Experts Exchange
0

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