BinaryRead and inserting into SafeArray

Why do you use Request.BinaryRead ?? The only reason would be that it contains binary code (from fileupload).

If not, then just use
Request.Form & "&Total=" & Server.URLEncode($100)

Else you have to do something like:

Request.BinaryRead & StringToByte("&Total=" & Server.URLEncode($100))

Where StringToByte is a userdefined function to convert a string to a byte.

Simplest Function for that is:

Function String2Byte(s)
    Dim sChar, i
    For i = 1 to Len(s)
        sChar = Mid(s, i, 1)
        String2Byte = String2Byte & ChrB(Asc(sChar))
    Next
End Function

(But use it only for small strings, for large strings it is very slow, and there are faster functions then)

xmlhttp was used so to post to asp pages in different servers and for later expansion, and for load balancing etc... I'm not at a liberty to change it.

oXMLHTTP.Send Request.BinaryRead & StringToByte("&Total=" & Server.URLEncode($100)) results in an error "type mismatch" as Send() expects an HTTPRequest (in the form of a safearray??)

manny

xmlhttp was used so to post to asp pages in different servers and for later expansion, and for load balancing etc... I'm not at a liberty to change it.

oXMLHTTP.Send Request.BinaryRead & StringToByte("&Total=" & Server.URLEncode($100)) results in an error "type mismatch" as Send() expects an HTTPRequest (in the form of a safearray??)

manny

xmlhttp was used so to post to asp pages in different servers and for later expansion, and for load balancing etc... I'm not at a liberty to change it.

oXMLHTTP.Send Request.BinaryRead & StringToByte("&Total=" & Server.URLEncode($100)) results in an error "type mismatch" as Send() expects an HTTPRequest (in the form of a safearray??)

manny

don't refresh this page: your comments get repeated !!

Now I remember a bit more:
If forms are posted with multipart/form-data, then you also need a seperator. The seperator is different everytime. You'll have to understand the mechanism quite well to add something to it.

'----mypage1.asp---------

    Set oXMLHTTP = Server.CreateObject("MSXML2.ServerXMLHTTP.4.0")
    oXMLHTTP.Open "POST", "http://mysite.com/mypage2.asp", False
    vntPostedData = Request.BinaryRead (Request.TotalBytes)
    oXMLHTTP.Send vntPostedData
'-------------------------
here again, I need to add one more variable to the Request in "mypage1" before I post to "mypage2" via xmlhttp... any way I could do this?

thanks
manjil

but now that I think of it. It would be a lot easier to add your extra values to the querystring:


sUrlToPostTo = "http://mysite.com/mypage2.asp?Total=" & Server.URLEncode("$100")

Set oXMLHTTP = Server.CreateObject("MSXML2.ServerXMLHTTP.4.0")
oXMLHTTP.Open "POST", sUrlToPostTo, False
vntPostedData = Request.BinaryRead (Request.TotalBytes)
oXMLHTTP.Send vntPostedData

and then read the request.querystring on the receiving site

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