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Assigning letters a value

Posted on 2003-03-01
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Last Modified: 2010-04-04
Hey all,
  What I'm trying to do is break down a word and assign a value to each letter, so it needs to work with upper and lowercase just the same.  The values range from 1-9 and get assigned in order of the letters and when it reaches 9 it starts at 1 again (ie. A-1,B-2,I-9,J-1).  Then I need it to add the assigned values together.

Thanks.
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Question by:Quantum
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4 Comments
 
LVL 3

Expert Comment

by:ILE
ID: 8049588
wery easy   100% working solution
  this assume that in string is only leters

  s:='enyword';
  rez:=0;
  for j:=1 to length(s) do
    rez:=rez+((ord[upcase(s[j])]-65) mod 9)+1;


this code if in word u mey have and other things like spaces numbers or enything else

  s:='enyword';
  rez:=0;
  for j:=1 to length(s) do
    if upcase(s[j]) in ['A'..'Z'] then
     rez:=rez+((ord[upcase(s[j])]-65) mod 9)+1;



wery easy arent?


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LVL 15

Accepted Solution

by:
VGR earned 2000 total points
ID: 8051750
numerology ? :D

I have a lot of code...

Interface

Function Chiffrage(par:string):string;
Function Chiffre(par:char):byte;

Implementation

Function Chiffre;
 Var chif : byte; { ATTENTION : ne s'appliquera qu'aux LETTRES. }

Begin
  chif:=(Ord(UpCase(par))-64);
  Case chif Of
    1..9  : Chiffre:=chif;
   10..18 : Chiffre:=(chif-9);
   19..26 : Chiffre:=(chif-18);
   End; { of CASE }
End;

Function Chiffrage;
 Var lresult : string;
     i      : byte;
     ch     : string; { car bug de TPv4.0 : tjrs pas Char=st1 ! }

Begin
  lresult:=par;
  For i:=1 to Length(par) Do
   Begin
     Str(Chiffre(par[i]),ch);
     lresult[i]:=ch[1];
   End;
  Chiffrage:=lresult;
End;
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Expert Comment

by:CleanupPing
ID: 9316991
Quantum:
This old question needs to be finalized -- accept an answer, split points, or get a refund.  For information on your options, please click here-> http:/help/closing.jsp#1 
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LVL 15

Expert Comment

by:VGR
ID: 9331691
split

or paq & norefund
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