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Using Wildcards

Posted on 2003-03-02
Medium Priority
Last Modified: 2010-04-17
I am trying to validate whether an e-mail address is in the correct format or not. Why does this not work?

If Trim(txtTo.Text) = "*@*.*" Then
MsgBox "Good"
MsgBox "Bad"
End If

It seems that it always returns bad, unless I actually type "*@*.*". Why are the wildcards not working properly?
Question by:Produkt
LVL 101

Expert Comment

ID: 8054169
Wildcards do not work across the = sign.  You need to use a string function that accepts the wildcard.

Wildcards were added for database usage to allow for comparison based on a substring.

What you want to have is code to parse the address to see if meets the proper format.

I think if you look at


you will find the code you need.


Accepted Solution

taisk earned 80 total points
ID: 8054245
This is because in VB, text comparison is not wildcardable.  The only time the expression Trim(txtTo.Text) = "*@*.*" is true is, as you suggested, when you actually enter "*@*.*".

What you can do instead is to use the instr command.

v = Trim(txtTo.Text)
If InStr(v, "@") > 1 And InStr(v, ".") > InStr(v, "@") + 1 And Mid(v, Len(v), 1) <> "."  Then
MsgBox "Good"
MsgBox "Bad"
End If

Author Comment

ID: 8054491
Works perfectly. Thank you.

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