Convert 16 Bit Register (HEX) to Decimal
Hi, I need a chunk of code that will convert a hex value in AX (16 BIT!) and store it somewhere in the data segment I dont care where you store it in the code I will change that later....if possible can you make the code NOT change as much as possible thanks
thanks
-brian
thanks
-brian
Here is my lame code;)
data segment
;...
result db 3 dup (' ')
termi db 0ah, 0dh, '$'
num1 dw 0
radix dw 10 ;decimal
data ends
;convert the ax to string, and save it to es:di(result)
ChangeResult2String proc
push es ; es = ds; only available for 16bit DOS
push ds
pop es
mov di, offset termi-1
std
loooop:
xor dx, dx
div [radix]
add dx, '0' ;convert the remainder to ascii
push ax
mov al,dl
stosb ;store al to ES:DI
pop ax
cmp ax, 0 ;check if the quotient = 0
je finish
jmp loooop
finish:
pop es
ret
ChangeResult2String endp
data segment
;...
result db 3 dup (' ')
termi db 0ah, 0dh, '$'
num1 dw 0
radix dw 10 ;decimal
data ends
;convert the ax to string, and save it to es:di(result)
ChangeResult2String proc
push es ; es = ds; only available for 16bit DOS
push ds
pop es
mov di, offset termi-1
std
loooop:
xor dx, dx
div [radix]
add dx, '0' ;convert the remainder to ascii
push ax
mov al,dl
stosb ;store al to ES:DI
pop ax
cmp ax, 0 ;check if the quotient = 0
je finish
jmp loooop
finish:
pop es
ret
ChangeResult2String endp
ASKER
I am really not understanding your code...here is what I am doing...I have the HEX VALUE "0B40", in AX, I have played with your code a little and I dont see what it is doing...mov di, offset termi-1? it looks like you are overwriting the CRLF? that is in termi? Could you give me a little more help with this, because it doesnt look like anything is being stored in any of the memory locations of those variables...
-brian
-brian
ASKER
dont you need to do
mov ax,@data
mov es,ax
???
mov ax,@data
mov es,ax
???
ASKER
dont you need to do
mov ax,@data
mov es,ax
???
mov ax,@data
mov es,ax
???
Hi Brian,
This is not a complete program, only a code snippet, used to convert ax to a string that stores in "result", it will not overwrite the CRLF, because before doing this, I called "std".
Yes, you can also use "mov ax,@data then mov es, ax",
but for most situations, the ds already point to the correct segment.
This is not a complete program, only a code snippet, used to convert ax to a string that stores in "result", it will not overwrite the CRLF, because before doing this, I called "std".
Yes, you can also use "mov ax,@data then mov es, ax",
but for most situations, the ds already point to the correct segment.
ASKER CERTIFIED SOLUTION
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The following works, and preserves all registers (except flags)
PUSH AX
PUSH DX
PUSH CX
PUSH SI
PUSH DI
MOV DI,OFFSET CONVS+4
MOV SI,10 ;constant divisor
MOV CX,5 ;#loops
DIVLP:
XOR DX,DX ;DX := 0
DIV SI
ADD DL,'0' ;to decimal
MOV [DI],DL ;put
DEC DI ;next char position
LOOP DIVLP
POP DI
POP SI
POP CX
POP DX
POP AX
CONVS:
DB 5 DUP (?)
HTH
...Bill
PUSH AX
PUSH DX
PUSH CX
PUSH SI
PUSH DI
MOV DI,OFFSET CONVS+4
MOV SI,10 ;constant divisor
MOV CX,5 ;#loops
DIVLP:
XOR DX,DX ;DX := 0
DIV SI
ADD DL,'0' ;to decimal
MOV [DI],DL ;put
DEC DI ;next char position
LOOP DIVLP
POP DI
POP SI
POP CX
POP DX
POP AX
CONVS:
DB 5 DUP (?)
HTH
...Bill
ASKER
BeyondWu:
div [radix] is causing my program to crash, It looks like its crashing because of a Division By Zero...help please :/
-brian
div [radix] is causing my program to crash, It looks like its crashing because of a Division By Zero...help please :/
-brian
Are you using my sample?
If you use it within your own code, please check if the value [radix] when debug, or post your code.
please check if the value [radix] == 0 when debug.
if so the [radix]==0, it always caused by the wrong value of DS, please ensure you have set in correctly with " mov ax, data; mov ds, ax".
ASKER
awesome! I can take it from here, thanks for all your help
ASKER