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parseDouble parameters

Posted on 2003-03-05
Medium Priority
Last Modified: 2008-02-01
I'm using parseDouble to convert String amounts to a double format. My string has commas as decimal separators (i.e 1,000,000.00) parseDouble throws an error when trying to convert the numbers with commas. Is there a way to tell parseDouble to ignore the commas or do I have to remove the commas from my string prior to sending it to parseDouble?
Question by:ahamel77
  • 2
LVL 35

Accepted Solution

girionis earned 300 total points
ID: 8072972
 Try this:

    NumberFormat formatter = new DecimalFormat("#,###,###.##");
    Number s = formatter.parse("1,234,000.56");
catch (ParseException pe)
LVL 35

Expert Comment

ID: 8072979
 You have to import the java.text.*; package for the above to work.

Expert Comment

ID: 8073113
The sites below are the best that can be found for explaining every class in the Java language.

http://java.sun.com/j2se/1.3/docs/api/index.html SDK 1.3 documentation
http://java.sun.com/j2se/1.4/docs/api/index.html SDK 1.4 documentation
LVL 30

Expert Comment

by:Mayank S
ID: 8110100
If removing the commas is OK with you, then do this:

// assuming 'str' is the string that contains the string-form of the double number
// Use a temporary StringBuffer object for removing the commas

StringBuffer sb = new StringBuffer ( str ) ;

for ( int i = 0 ; i < sb.length () ; i ++ )
  if ( sb.charAt ( i ) == ',' )
    sb.deleteCharAt ( i ) ;
    i -- ; // not needed as there won't be successive commas, but no harm in putting this statement

  } // end if, for

double doubleVal = Double.parseDouble ( sb.toString () ) ;

This will remove all commas from the StringBuffer object and then pass its string-equivalent to parseDouble (). This way, 'str' will retain its original value (including commas). If you want it to hold the new value, then you can do:

str = sb.toString () ;
double doubleVal = Double.parseDouble ( str ) ;

Hope that helps!


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