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Option field - Start at top

Posted on 2003-03-06
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Last Modified: 2008-03-06
I have a form that has 3 option fields.

They seem to be defaulting to the center of the list (probably the last record that I entered's value).  I need this to always start at the top.  For instance, if I was using the USA for a state list, it might start in South Dakota, not Alabama.  Thoughts?
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Question by:palare98
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7 Comments
 
LVL 15

Expert Comment

by:VGR
ID: 8083458
provide the desired OPTION with a well-placed SELECTED attribute ;-)
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Author Comment

by:palare98
ID: 8083788
I don't understand.
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LVL 15

Expert Comment

by:VGR
ID: 8084250
unless I did misunderstand you,
you want that one of the OPTIONs is selected in stead of the last one inserted (or the first one in alphabetical order, IMHO)

Then your SELECT should look like this :

<SELECT NAME=state>
<OPTION NAME="Alabama">Alabama</OPTION>
<OPTION NAME="South Dakota" SELECTED>South Dakota</OPTION>
</SELECT>
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Author Comment

by:palare98
ID: 8084464
Did I leave out the part that this is being dynamically generated from a seperate table?  I'm sorry.  Does it work the same way?  Or is there a way to always start at the beginning, regardless of what the beginning is?  If this drastically changes the question, I'll up the points.
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LVL 15

Accepted Solution

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VGR earned 200 total points
ID: 8084591
no, it doesn't change anything. Of course that I suspected you had a query running somewhere to generate the states' names (for example) : nobody would be fool enough to enter them by hand :D :D

If you want do have always the first element selected by default, then simply do this in your while loop (if a for loop, it's even simplier)

echo "<SELECT>";
$i=0;
while ($res=mysql_fetch_array(blahblahblah)) {
  // read $statename from $res["statename"] for example
  $i++;
  echo "<OPTION NAME=\"$statename\" ".(($i==1)?'SELECTED':'').">$statename</OPTION>";
} // while
echo "</SELECT>";
0
 

Author Comment

by:palare98
ID: 8084629
I can't test this until the morning...Thanks...I'll let you know how it turns out.
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Author Comment

by:palare98
ID: 8103796
I don't have time to test this...I'm sorry.  I'm sure that its righteous.  Thanks for he answer.
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