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HTML:Parser cgi script (part 2)

Posted on 2003-03-15
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Last Modified: 2010-03-05
My previous question asked for:-

1. The first 8 characters of the url ie: ' awebsite ' or everything between www. and .com (or whatever after . ie .net .co.uk .org) if the address has less than 8 characters. If the address is a repeat then add number
(incremented) ' awebsite_1 '.

answer accepted (snip):-

while( <L> ){
   chomp;
   ($u) = m'//(?:www\.)?([^.]{0,8})';
   if( $n = $n{$u}++ ){ $u .= "_$n"; }


I need the code to return only characters (letters of the alphabet) & numbers ( 0 - 9 )so if there were any other characters in the web address such as a forward slash ( / )it would ignore those.

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Question by:malkie
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2 Comments
 

Accepted Solution

by:
trevorw earned 500 total points
ID: 8143102
Hi,

You can replace all non-alphanumeric characters in the url's as follows:

while (<L>) {
  ($u) = m'//(?:www\.)?([^.]{0,8})';
  $u =~ s/\W//g;
  if( $n = $n{$u}++ ){ $u .= "_$n"; }
}

There is probably a way to incorporate this into the original regexp but I'm not too hot on them :)

Hope this helps.

Best regards,
Trevor
0
 

Author Comment

by:malkie
ID: 8146696
Thanks Trevor works okay for me God Bless
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