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position of variables in a list

Posted on 2003-03-16
Medium Priority
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Hi,

I've a small problem.
I'm making a very simple cashregister program.  It this program, I use a list to add items.
Each item in that list have to contain 3 variables.
For example:

3   Cola                                  4,5
5   Fanta                                 6,5

'and so on

NOW HERE IS THE PROBLEM:
As in the example the '3' is stored in a variable1, the 'cola' in variable2 and the '4,5' in variable3.

Now I do the following:

List1.AddItem variable1 & vbTab & variable2 & vbTab & vbTab & vbTab & vbTab & vbTab & variable3

The problem is, when the characters or numbers stored in some of these variables ar longer I get this:

3   Cola                                  4,5
5   Fanta                                 6,5
3   The best beer                                9,5
5   Fristi                                8,0

As you can see in the 3th line, the 9,5 sticks out.  Does anyone have the solution to this problem.
(keep in mind, it's a very easy program so I dont want to use (or connect to) a database)
For example: Is it possible to declare each position of each variable, starting from the left edge of the list??)

Vincent
0
Question by:vincentregent
• 2

LVL 2

Accepted Solution

Sweat earned 240 total points
ID: 8147300
vincentregent,

Easy "problem" to fix.

To properly align the three variables, you need to insure that all of the rows added to the listbox are of the same length.  So when you are dealing with the "3" or Variable1, then if you have more than ten rows and a value of two characters, then the "3" must be "3 ".

The same is true for the other two variables.  You'll need to pick a length, say 20 characters and insure that each variable2 is the same length.

Consider the following method:

Variable1 = "Cola"
Variable1 = Variable1 & Space\$(20 - Len(Variable1))
would become: "Cola                "

or

Variable1 = "The best beer"
Variable1 = Variable1 & Space\$(20 - Len(Variable1))
would become: "The best beer       "

Then when you build the Additem line, each line will be of the same length and therefore lined up.

Let me know if this isn't clear.

Sweat

0

Author Comment

ID: 8147440
Thanks a lot Sweat !!!!!!

Greetings,
Vincent
0

LVL 3

Expert Comment

ID: 8147480

If you need to stay with the Tab as a separator, you could use a function like this:

Private Sub Command1_Click()
List1.Clear

a = 3: b = "The best beer": c = "9,5"
List1.AddItem CheckWidth(a, "1234") & CheckWidth(b, "1234567890") & c

a = 3: b = "Cola": c = "4.5"
List1.AddItem CheckWidth(a, "1234") & CheckWidth(b, "1234567890") & c

a = 5: b = "Fanta": c = "6, 5"
List1.AddItem CheckWidth(a, "1234") & CheckWidth(b, "1234567890") & c

End Sub
Function CheckWidth(strT, strMaxWidth) As String
'We put at least one vbTab
strMaxWidth = strMaxWidth & vbTab

Me.Font = List1.Font
Me.FontSize = List1.FontSize

If TextWidth(strT & vbTab) > TextWidth(strMaxWidth) Then
MsgBox "Text too long :" & strT

Else

separator = ""
Do While TextWidth(strT & separator) < TextWidth(strMaxWidth)
separator = separator & vbTab
Loop

Do While TextWidth(strT & separator) < TextWidth(strMaxWidth)
If separator = "" Then Exit Do
separator = Mid(separator, 2)
Loop

End If

CheckWidth = strT & separator

End Function
0

Author Comment

ID: 8152448

Vincent
0

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