cjesgo
asked on
String Manipulation...
I need to create a function that will take a string from and input box (say a first name), read it one character at a time and redisplay it to the user. This is a school project so I can do this however I chose. My thought was to have a user input his name, the function would count the characters in the string, and redisplay it in a label box. I need help creating this function. I toyed around with the
Len(), and Mid() but I am lost.
Len(), and Mid() but I am lost.
we can't do your homework for you, however, if you post what you have so far, i'm sure we can help you towards a solution
ASKER
bobbit31 - after rereading my post I guess that is how I came across...sorry. I just need a some guideness. Here is what I have:
Dim strFirst As String
Dim strLast As String
Dim strFull As String
'Get the first name for the textbox
strFirst = txtFname.Text
'Get the last name from another textbox
strLast = txtLname.Text
'Concatenate the first and last name, putting
'a space character between them.
strFull = strFirst & " " & strLast
'Display the Full Name
lblResult.Caption = strFull
Dim szText As String
Dim nStartingFrom As Integer
Dim nNumChars As Integer
'-- Assign szText
szText = txtFname.Text
'-- Set the starting position
nStartingFrom = 1
'-- Set the number of characters
nNumChars = 1
'-- Print the partial string
Print Mid$(szText, nStartingFrom, nNumChars)
I imagine I need some sort of counter to keep track of how many characters in the string correct? Thanks.
Dim strFirst As String
Dim strLast As String
Dim strFull As String
'Get the first name for the textbox
strFirst = txtFname.Text
'Get the last name from another textbox
strLast = txtLname.Text
'Concatenate the first and last name, putting
'a space character between them.
strFull = strFirst & " " & strLast
'Display the Full Name
lblResult.Caption = strFull
Dim szText As String
Dim nStartingFrom As Integer
Dim nNumChars As Integer
'-- Assign szText
szText = txtFname.Text
'-- Set the starting position
nStartingFrom = 1
'-- Set the number of characters
nNumChars = 1
'-- Print the partial string
Print Mid$(szText, nStartingFrom, nNumChars)
I imagine I need some sort of counter to keep track of how many characters in the string correct? Thanks.
Do you mean something like this:
Dim MyValue As String
MyValue = InputBox(Message, Title, Default, 100, 100)
Dim TempChar As String
Dim CountChar As Integer
For I = 1 To Len(MyValue)
CountChar = CountChar + 1
TempChar = TempChar + Mid(MyValue, I, 1)
Next I
Label1.Caption = TempChar
Label2.Caption = CountChar
Dim MyValue As String
MyValue = InputBox(Message, Title, Default, 100, 100)
Dim TempChar As String
Dim CountChar As Integer
For I = 1 To Len(MyValue)
CountChar = CountChar + 1
TempChar = TempChar + Mid(MyValue, I, 1)
Next I
Label1.Caption = TempChar
Label2.Caption = CountChar
Short of doing your project for you, here's an example of how to use a FOR loop to display the string one character at a time. This will display the results to a text box called Text1.
e.g.
Private Sub ShowResults(sINPUT As String)
For i = 1 To Len(sINPUT)
Text1.Text = Text1.Text & Mid(sINPUT, i, 1)
Next i
End Sub
e.g.
Private Sub ShowResults(sINPUT As String)
For i = 1 To Len(sINPUT)
Text1.Text = Text1.Text & Mid(sINPUT, i, 1)
Next i
End Sub
> I imagine I need some sort of counter to keep track of how many characters in the string correct? Thanks
no, that's what the Len function is for
msgbox Len(szText)
no, that's what the Len function is for
msgbox Len(szText)
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Thunder27 - Thanks! I guess I was closer than I thought.