Visual Basic Shell Command

I want to use a Shell command in my VB 6.0 application to start an executable.  I want to pass it four parameters.  Is this possible and if so, how would I do it?
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Shell "c:\yourexe.exe"
What exactly do you mean with parameters ?

Like Shell "Yourexe.exe /p=blahblah"
It's exactly the same way you would pass it parameters in the run dialog.

e.g. To open Windows Media Player with a file you would type:

wmplayer.exe C:/File.wav

into a run dialog box (the '.exe' is not necessary)

In VB6 you do the same thing:

Call Shell("wmplayer.exe C:/File.wav")

Hope that helps.

Sinister Shadow
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As previously stated,

Shell("your.exe /parm1 /parm2 /parm3 /parm4")

But then, how do you read the parameters? Well, in your start up code for the target exe (most likely your Sub Main()) use the Command function something like this:

Sub Main()
Dim sArray() as string
If Len(Command) > 0 Then
  sArray = Split(Command, , Space(1), 4)
  MsgBox "Parm 1 Value: " & sArray(0)
  MsgBox "Parm 2 Value: " & sArray(1)
  MsgBox "Parm 3 Value: " & sArray(2)
  MsgBox "Parm 4 Value: " & sArray(3)
End If
End Sub


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Richie_SimonettiIT OperationsCommented:
optionally, you could use ShellExecute API:

Private Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As Long) As Long

Sub LaunchExe()
shellexceute 0,"open","c:\myfile.exe","parameters goes here",vbnullstring,vbnormal
end sub
Richie_SimonettiIT OperationsCommented:
Sub LaunchExe(sExePath as string)
shellexecute 0,"open",sExePath,"parameters goes here",vbnullstring,vbnormal
end sub
Hi PJS123,
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