Assigning Shift to a variable

Posted on 2003-03-27
Medium Priority
Last Modified: 2012-05-04
I am in the process of learning perl. I came through a piece of code where the shift operator is being assigned to a variable. The code is something like this:

my ($var1) = shift;

I am not quite able to understand what exactly happens here and how this work? Can someone please explain?

Question by:akila76
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Accepted Solution

ozo earned 100 total points
ID: 8222441
perldoc -f shift
       shift ARRAY

       shift   Shifts the first value of the array off and
               returns it, shortening the array by 1 and moving
               everything down.  If there are no elements in the
               array, returns the undefined value.  If ARRAY is
               omitted, shifts the `@_' array within the lexical
               scope of subroutines and formats, and the `@ARGV'
               array at file scopes or within the lexical scopes
               established by the `eval ''', `BEGIN {}', `INIT
               {}', `CHECK {}', and `END {}' constructs.

Author Comment

ID: 8222462
Thanks a lot

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