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Quaternion problem

Posted on 2003-03-30
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Last Modified: 2013-12-26
I'm using quaternions to navigate a "space ship" in a 3D world. The mouse is used to point the ship in any desired direction, and that part is working just fine. The problem is that I don't know how to actually move the ship in the direction I'm facing.
So the question is: How do I get the values to put in the glTranslate-function, given a quaternion that describes the current rotation?

I'm using openGL and C.

/Peter
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Question by:Pegu
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6 Comments
 
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Expert Comment

by:Hermetic
ID: 8236559
A simple method would be to express the spaceships velocity as a vector and apply the quaternion rotation to that vector.  Then you could translate your spaceship using the rotated velocity vector.
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Author Comment

by:Pegu
ID: 8237163
Ok... I had pretty much figured that much out. I'm afraid the problem here is the math part. Lets say I have a rotation quaternion (w=0.92,x=-0.38,y=0,z=0). This would have me heading upwards at an angle of about 45 degrees (with the Z-axis as the default direction) and thus giving a vector looking something like (0.7,0.7,0.0).
But how exactly do I apply the quaternion to the velocity vector in order to reach this result?
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Author Comment

by:Pegu
ID: 8237197
Oops.. The velocity vector in the above example should of course be (0.0,0.7,0.7).
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Expert Comment

by:Aleph
ID: 8240618
To rotate a vector with a quaternion, do the following:

(0, rotatedVector) = q_conj * (0, vector) * q

Where q is the quaternion, q_conj is q conjugated and (0, vector) is the vector expressed as a quaternion with the w component set to 0.
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Author Comment

by:Pegu
ID: 8246832
Hmmm, still can't make it work..
Ok, let me see if I've understood this.
Let's say the negative z-axis is my default direction. I'm heading 45 degrees upwards with a rotation quaternion (w=0.92, x=-0.38, y=0, z=0) and a velocity vector (0.0, 0.707, -0.707). I then turn 20 degrees upwards giving me a rotation quaternion (w=0.84, x=-0.537, y=0, z=0).

So to find the new velocity vector (0.0, 0.906, -0.423) I would calculate (0.84,0.537,0.0,0.0) * (0.0,0.0,0.0,-1.0) * (0.84,-0.537,0.0,0.0), with Q1*Q2=(w1.w2 - v1.v2, w1.v2 + w2.v1 + v1*v2)?
Or should the middle term, (0.0, vector), be the current velocity vector (0.0,0.707,-0.707)?

This quaternion math is a bit hard to grasp, so I could really use a more extensive example!
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Accepted Solution

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Aleph earned 200 total points
ID: 8253394
The middle quaternion is constructed from you current vector.  If you have a quaternion q representing a rotation, you form a quaternion qv from your vector by letting the w element of qv be zero, and the other elements correspond to the vector elements. The rotation is then performed by doing the quaternion multiplication q_conj * qv * q, giving you a new quaternion which represents your new, rotated vector. Just skip the w element in it (which is zero) and you have your new vector.

Example:
If you want to rotate the vector (0.0, 0.707, -0.707) with the quaternion (w = 0.84, x=-0.537, y=0, z=0) you do the quaternion multiplication:

(0.84, 0.537, 0, 0)*(0, 0, 0.707, -0.707)*(0.84, -0.537, 0, 0) = Q

After that you have your new vector as x, y, z in Q. I assume you know how to multiply quaternions. Otherwise, tell me.

To combine two rotations, each represented by a quaternion, you just multiply them. q = q1 * q2 will be equivalent of a rotation first by q1 and then by q2.

This is because: (q1*q2).conj * qv * (q1*q2) = q2.conj * q1.conj * qv * q1 * q2

Actually, one can also rotate vectors by doing q * qv * q.conj instead. This corresponds to the inverse rotation of what I have described above. Combining two rotations is then done in the opposite way, that is q = q2 * q1. Which one you use depends on how you create the quaternion. It is a matter of taste really. When I think about it, the latter convention is probably the more common, albeit not the one described by Shomake in the original paper about quaternions.
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