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How do I return a string from C++ DLL?

Posted on 2003-10-21
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Last Modified: 2010-04-01
Hello,

I have the following C++ code in a DLL which all works fine. However, it is horribly inefficient. Please help to simplify.  

(1) Here is the working C++ function:

__declspec(dllexport) LPSTR __stdcall PopStrData2(const char *object, char *retval){
      if(object == NULL) object = "";
      BPCHAR p;
      if(!BeginTransaction()) return FALSE;
      if(!Pop(&pSharedData->pStrStacks, object, &p)) {EndTransaction();return FALSE;}
      strcpy(retval, p);
      hfree(p);
      EndTransaction();
      return retval;
}

(2) I am calling the function from another program in the format:

Dim Buffer="                                            "
MyString = PopStrData2("OBJECT", Buffer)


(3) QUESTION

Is there someway to get rid of the "char *retval" parameter in the C++ function PopStrData2(const char *object, char *retval) ?

In otherwords, I want to simply call:

Dim MyMsg as String
MyMsg = PopStrData2("OBJECT")

What changes do I need to make to my C++ dll function?

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Question by:deming
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4 Comments
 
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Accepted Solution

by:
dualsoul earned 125 total points
ID: 9597292
VB can't work directly with char* datatype in C++.
So you shoul use BSTR type in your C++ code and using global memory allocation for it.You can do it by using
family of function: SysAllocString

for instance: (creating a string):

   BSTR string=SysAllocString(OLESTR("some string")); //note BSTR is unicode string, not as char*
  *result=&string; //return result to VB
   
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Expert Comment

by:Daij-Djan
ID: 9601519
BSTR is unicode too btw
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LVL 15

Expert Comment

by:dualsoul
ID: 9601569
> BSTR is unicode too btw

it's just what i've said :)
BSTR is the pointer to sequence 16bit character
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LVL 5

Expert Comment

by:Daij-Djan
ID: 9601606
upsi ;) Didnt see that.
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