nicolle
asked on
IP validation ?
How do I use Javascript to do IP validation ? The IP validation will validate 255.255.255.255 or 0.x.x.x as invalidate IP. Any sample ?
ASKER
your code does not accept 1.1.1.1.
Sorry ! I should state clear to you. In my case, 255.255.255.255 and first part begin
with 0 are invalid.
Sorry ! I should state clear to you. In my case, 255.255.255.255 and first part begin
with 0 are invalid.
ok so
var objRegExp = /^[1-9]{1,3}\.{1}\d{1,3}\.
is 255.255.255.255 invalid
var objRegExp = /^[1-9]{1,3}\.{1}\d{1,3}\.
is 255.255.255.255 invalid
ASKER
Yes, 255.255.255.255 is invalid
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:))) LOL
if(fObj["ip"].value == "255.255.255.255")
<-- That was funny !
I would double points for that!
if(fObj["ip"].value == "255.255.255.255")
<-- That was funny !
I would double points for that!
ASKER
makc,
You have better regular expression on that ?
You have better regular expression on that ?
actually, i don't see why to use regexp at all. make four inpus for each byte, use isNaN(input.value) and check it to be in 1...254 range. that's it, isn't it?
isNaN(parseInt(input.value
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<script type="text/javascript">
<!--Begin
function isIPaddy(strValue){
// 255 . 255 . 255 . 255
var objRegExp = /^\d{3}\.{1}\d{3}\.\d{3}\.
return objRegExp.test(strValue);
}
function validateForm(fObj){
if(!isIPaddy(fObj["ip"].va
alert("Please enter a correct IP address\n\nEx. 255.255.255.255");
fObj["ip"].select();
return false;
}
return true;
}
//End-->
</script>
</head>
<body>
<form name="form1" method="post" action="" onSubmit="return validateForm(this);">
<input type="text" name="ip">
<input type="submit" name="btnSubmit" value="Submit">
</form>
</body>
</html>