Push Buttons

Hi everybody,

I made a simple MFC Dialog based application. In this i created two push buttons. I want to toggle the state of the button if it is being clicked.

I added these to command handlers to act on each click on the button.

void CDialogDlg::OnBtn1()
{
  static bool b_Btn1 = !b_Btn1 ;  // to trace the state of the button

  m_Btn_Right.SetState(bBtn1) ; // I tried 0x004 and FALSE also
}

void CDialogDlg::OnBtn2()
{
  static bool b_Btn2 = !b_Btn2 ;  // to trace the state of the button

  m_Btn_Right.SetState(bBtn2) ; // I tried 0x004 and FALSE also
}

when you click on one button it is working fine.... But first clicking on Btn1 and then clicking on Btn2 (or vice-versa) changes the state of both buttons.......

Can anybody figure it out why it happens so ???


Dennis
LVL 5
dennis_georgeAsked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

dennis_georgeAuthor Commented:
hi,

 I am using VC 6

Dennis
0
_nn_Commented:
You're referencing the same object, so it's normal. I would try :

void CDialogDlg::OnBtn1()
{
  static BOOL b_Btn1 = !b_Btn1 ;  // to trace the state of the button

  m_Btn_Left.SetState(bBtn1) ;  // the LEFT button
}

void CDialogDlg::OnBtn2()
{
  static BOOL b_Btn2 = !b_Btn2 ;  // to trace the state of the button

  m_Btn_Right.SetState(bBtn2) ; // the RIGHT one
}
0
dennis_georgeAuthor Commented:
Hi.....

 I like to add one more thing.......

 If I change the state of a button, as pressed (or DOWN), and then make the dialog out of focus then the state of the button changes automatically(i.e. UP state) .....

(e.g.  if Btn1 is DOWN and I pressed Btn2 then the OnBtn1() is called first and then OnBtn2() is called ....
 Can anybody tell me from where and who and Why does Btn1() is called...
 )

 I think during the drawing of the button either the buttons state is changed or drawn with wrong state...

 I don't know whether i am doing something wrong or there is some BUG here in handling setstate of the button.......



Dennis
0
Become a CompTIA Certified Healthcare IT Tech

This course will help prep you to earn the CompTIA Healthcare IT Technician certification showing that you have the knowledge and skills needed to succeed in installing, managing, and troubleshooting IT systems in medical and clinical settings.

_nn_Commented:
See :
http://msdn.microsoft.com/library/default.asp?url=/library/en-us/vcmfc98/html/_mfc_cbutton.3a3a.setstate.asp

<quote>
A button control is automatically highlighted when the user clicks and holds the left mouse button. The highlighting is removed when the user releases the mouse button.
</quote>

If you need to change this behavior, I'm afraid it's gonna be somewhat more complicated than just using CButton::SetState()... What are you trying to do exactly here ?

0
AlexFMCommented:
void CDialogDlg::OnBtn1()
{
 static bool b_Btn1 = false;
 b_Btn1 = ! b_Btn1;

 m_Btn_Right.SetState(bBtn1) ;
}

void CDialogDlg::OnBtn2()
{
 static bool b_Btn2 = false;
 b_Btn2 = !b_Btn2 ;  // to trace the state of the button

 m_Btn_Right.SetState(bBtn2) ;
}

I am not sure that this is highlighting you want: highlighting affects the exterior of a button control.
0
dennis_georgeAuthor Commented:
Then what is the purpose of SetState ?? If "A button control is automatically highlighted when the user clicks and holds the left mouse button. The highlighting is removed when the user releases the mouse button".

This is the default action of a button.... From the MSDN i got only that  you can set the highlighting state of a button control using SetState....

I want two or more buttons with the following behaviours........
(A button can be in two state either UP or DOWN)
-- If the button is in UP state (Not highlighted) and I pressed it, then its state should change from UP to DOWN (Highlighted)... and it should remain in that state only until i press it again.....
-- If the button is in DOWN state (highlighted) and I pressed it, then its state should change from DOWN to UP ...
and it should remain in that state only until i press it again....

Dennis
0
SteHCommented:
Use a Checkbox and tick the box Push-like under styles on the property page. Now you have a button that holds its state until you click on it.
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
AndyAinscowFreelance programmer / ConsultantCommented:
As SteH says use a checkbox with the push style (resource editor).  You can then access it like a normal button.
eg ((CButton*)GetDlgItem(IDC_CHECK1))->
or create a member CButton variable linked to the control m_btn_Left
0
dennis_georgeAuthor Commented:
Thanx SteH.......

    I think my problem is solved ......

But Stil i don't get the use of SetState of Push Button (CButton)......

Dennis
0
SteHCommented:
For a push button you can use it to change its state by program code instead of a mouse click. For a normal button I can't really see a use for it. It is needed if you can use a shortcut key or a menu item to issue the same command. SetState allows to synchronize all values.
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
System Programming

From novice to tech pro — start learning today.