Using variables within XSL Output

Hi,

I would ask this directly in the XML section but the link doesnt appear to be working.

I have the following piece of XSL code which embeds an SVG image within my document:

<xsl:for-each select="Diagram">
      <embed height="163.8"  width="172.20">
      <xsl:attribute name="id">SVGDiagram</xsl:attribute>
      <xsl:attribute name="src"><xsl:value-of select="//XSLPath"/>media/svg/feet_XSL.svg</xsl:attribute>      </embed>
</xsl:for-each>

I need to change the name of the embed (SVGDiagram) to unique identifiers e.g. append a 1,2 etc. so the embed name would be SVGDiagram1, SVGDiagram2 etc.

I believe this may be possible through using the tag <xsl:variable within the attribute tag, or by using some script within CDATA sections. Can anyone shed any light?

Cheers

LVL 1
paulsidebottomAsked:
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wellileinCommented:
I think

<xsl:variable name="enumerate" select="0"></xsl:variable>
<xsl:for-each select="Diagram">
      <xsl:variable name="enumerate" select="$enumerate+1"></xsl:variable>
     <embed height="163.8"  width="172.20">
     <xsl:attribute name="id">SVGDiagram<xsl:copy-of select="$enumerate"></xsl:copy-of></xsl:attribute>
     </embed>
</xsl:for-each>

should work, but XML-Spy has trouble with redefining the variable enumerate. I already encountered the problem once and I think the solution was to take a different transformer.
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berni_brownCommented:
Hi,

How are you intending to access the XSL file, which XML processor are you using?

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wellileinCommented:
If the only purpose is to distinguish Names, you might try position()

<xsl:for-each select="Diagram">
<xsl:variable name="enumerate" select="position()"/>
     <embed height="163.8"  width="172.20">
     <xsl:attribute name="id">SVGDiagram<xsl:copy-of select="$enumerate"></xsl:copy-of></xsl:attribute>
     </embed>
</xsl:for-each>

This also works in XML Spy.
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paulsidebottomAuthor Commented:
Thanks but...my XSL translator (IE5.5) is having problems with the redefiniton of enumerate as well.

Problem is, due to the way the XML is structured (diagram elements are grouped under a parent ), all elements named diagram return a position of 1, hence I can't use <xsl:value-of select="position()">

Thanks for your input so far though!

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paulsidebottomAuthor Commented:
Sorry forgot to mention I am using MSXML3.0 XML parser
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wellileinCommented:
Ok, try using the position of another element, maybe the parent element.

      <xsl:for-each select="Parent">
            <xsl:variable name="enumerate" select="position()"></xsl:variable>
            <xsl:for-each select="Diagram">
                 <embed height="163.8"  width="172.20">
                 <xsl:attribute name="id">SVGDiagram<xsl:copy-of select="$enumerate"></xsl:copy-of></xsl:attribute>
                 </embed>
           </xsl:for-each>
      </xsl:for-each>

will work fine if Parent has a position and has only one diagram. (If the parent contains more than one diagram, you could perhaps define two variables and concatenate them.)
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paulsidebottomAuthor Commented:
Pure Genius! worked perfectly. Thanks a lot
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