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Opening an application through VB

Posted on 2003-10-28
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Last Modified: 2010-05-01
Hello,

I use a third party application...I believe that application was written in C. That application folder has, one exe and 13 dll files. Say, this application is present in C:\pace\app.exe along with the dll files.

When I double click this exe from Windows, the application opens and I am getting the first menu screen. Then, I naviagated to C:\pace in command prompt and typed app.exe. Again, the application opens and I am getting the first menu screen.

Now, I want to open the application through VB...To test this, I just put a command on a form and put the Shell statement code in Command1_click.

It opens a window for the application, but is a blank white window...I know the window is that of application, but why is it blank...why I am not getting the menu screen I was getting by just double clicking it or from the command prompt..I tried different methods of shelling using command.com, comspec etc..everything gives the same result..just opens a blank window!
I am sure my shell code is correct, but I believe it may have something to do with dlls or paths etc...

Could any one please help me out here..Please bear with me as I am short of points..

Thanks
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Question by:vblycos
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Éric Moreau earned 50 total points
Comment Utility
use ChDir to change the current directory to c:\pace before shelling.
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by:vblycos
Comment Utility
Thanks emoreau, that did the trick!
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