simple Vector STL question

vector<string> names;

for(vector<string>::iterator i = names.begin(); i !=names.end(); i++ )
{
           //how do I want a pointer to the strings in names, how do i get it?
}


I need pass a string* to another function, i'm getting an error because i is an iterator, how can I recover the pointer to the string?
LVL 5
jjacksnAsked:
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AlexFMCommented:
for(vector<string>::iterator i = names.begin(); i !=names.end(); i++ )
{
    cout "String: " << *i << "  Length: " << (*i).length();
}
0
jjacksnAuthor Commented:
I need the actual string *, I don't just want to print it out.  How do I get it back?
0
AlexFMCommented:
*i is string itself. &(*i) is string*

for(vector<string>::iterator i = names.begin(); i !=names.end(); i++ )
{
    OtherFunction( &(*i) );    
}
0

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AxterCommented:
You can also point to the string const char via c_str() member function.

char data[99];
for(vector<string>::iterator i = names.begin(); i !=names.end(); ++i)
{
          strcpy(data, i->c_str());
}

Here's a more optimize loop:
for(vector<string>::iterator i = names.begin(), i_end = names.end(); i != i_end; ++i)
{
          strcpy(data, i->c_str());
}
0
fsign21Commented:
>I need pass a string* to another function, i'm getting an error because i is an iterator,
>how can I recover the pointer to the string?

May be, you want to do something like this?

using namespace std;
class VecStr
{
public:
  vector<string> names;

  string* findName(const string& val) {
    for(vector<string>::iterator i = names.begin(); i !=names.end(); i++ )
      {
        if((*i)==val)
          return &(*i);
      }
    return NULL;
  }
};

int main (int argc, char* argv[])
{
  VecStr vec;
  vec.names.push_back("Bob");
  vec.names.push_back("Ron");

  string* p = vec.findName("Bob");
  if(p) {
    cout << "Found" << endl;
  } else {
    cout << "Not Found" << endl;
  }
  string* p1 = vec.findName("Tom");
  if(p1) {
    cout << "Found" << endl;
  } else {
    cout << "Not Found" << endl;
  }
  return (0);
}

Output:
Found
Not Found
0
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