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Using a loop to count by a decimal increment

Posted on 2003-10-29
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Last Modified: 2012-06-22
I'm trying to make a loop that counts by .8, ie- user enters a starting digit, it takes that number and counts by .8 for a set ammount of times... I have already found one way to do it but im sure there has to be another because this one takes alot of effort, and display variables...


any tips will be appreciated
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Question by:canucks16
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4 Comments
 
LVL 16

Expert Comment

by:imladris
ID: 9643724
If you can use float you could do something like:

float lv;
cin>>lv;
for( ; lv<limit; lv+=0.8)
{   //loop code
}
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LVL 12

Accepted Solution

by:
andrewjb earned 50 total points
ID: 9643896
or do you mean

int lIndex;
float lValue;

lValue = //start value

for ( lIndex = 0 ; lIndex < lCount ; lIndex++ , lValue+=0.8)
{
  // use lValue here
}

?? What's the problem?
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LVL 16

Expert Comment

by:imladris
ID: 9651167
Did either of those answers help?

If so it is time to select one to close the question, and grade it.

If not, perhaps a clarifying question would help.
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LVL 12

Expert Comment

by:andrewjb
ID: 9656467
If that answer is right, don't 'C' grade it. If it isn't, say why. People get annoyed with low grades...
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